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Statistics Probability Question

Four letters are picked at random from the word THURSDAY. What is theprobability that there is at least one vowel among the letters?

(a)11/14(b)4/7(c)3/14(d)1/15

I'm just a bit confused about what to do.
I know the total number of possibilities is 8C4 =70 but I don't know where to go from there.
Help is appreciated, thanks in advance :smile:
Reply 1
Original post by jamesthelam
Four letters are picked at random from the word THURSDAY. What is theprobability that there is at least one vowel among the letters?

(a)11/14(b)4/7(c)3/14(d)1/15

I'm just a bit confused about what to do.
I know the total number of possibilities is 8C4 =70 but I don't know where to go from there.
Help is appreciated, thanks in advance :smile:


Let vv be the number of vowels picked.
P(v1)=1P(v=0)\mathbb{P}(v \geq 1) = 1- \mathbb{P}(v=0).
Now consider the ways one can pick no vowels at all.
Reply 2
Original post by joostan
Let vv be the number of vowels picked.
P(v1)=1P(v=0)\mathbb{P}(v \geq 1) = 1- \mathbb{P}(v=0).
Now consider the ways one can pick no vowels at all.


Thanks, now that I think about it, it's obvious :biggrin:
Reply 3
Original post by jamesthelam
Thanks, now that I think about it, it's obvious :biggrin:


It crops up fairly frequently -something to watch out for.

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