Logarithm help C2Watch

#1
Could someone please show me how to do the following two questions;

Given that logax=3 and logay-3loga2=4, express x in terms of a
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Find the value of x for which 8^x/√8=1/64

Thank you
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#2
(Original post by henb99)
Could someone please show me how to do the following two questions;

Given that logax=3 and logay-3loga2=4, express x in terms of a
------------------------------------------------------------------------------------------------------
Find the value of x for which 8^x/√8=1/64

Thank you
For the first part of the question, x in terms of a I think is just a^3 = x, as this comes from rearranging log of base a is equal to x.

For the second part of the question, see attached working. I plugged this into a calculator and it all checks out

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#3
(Original post by Dapperblook22)
For the first part of the question, x in terms of a I think is just a^3 = x, as this comes from rearranging log of base a is equal to x.

For the second part of the question, see attached working. I plugged this into a calculator and it all checks out

Thank you very much, thats perfect really appreciate it!
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