A question asks: in a group of 60 girls and 40 boys, it is found that the probability of a person being left handed is 0.18. The probability of a girl being left handed is 0.1. What is the probability of a boy being right handed?
I got this wrong and in the solution I'm not seeing what exactly the difference of being a girl and left handed P(AuB) = 0.1 and being left handed given one is a girl P(A|B)*
Could somebody please explain the difference?
*P(AuB) = P(A) * P(A|B)
therefore, P(A|B) = 0.1 / 0.6 = 1/6.
I can't intuit what exactly is being said here, when looking at u vs |