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    (Original post by HasanRaza1)
    Hmm why wouldnt they ask for the third harmonic if they wanted it? The way I interpreted it they wanted the basic frequency of the wave, which is a constant value
    yh i guess, i think you're right, how many marks do you i would lose for timesing it by 3 (1mark ?)
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    anyone able to do an unofficial mark scheme in the recent future??
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    For the one about why there would be no current belown a certain frequency. Anyone get that below the threshold frequency no photo electrons would be emitted therefore no current as the electrons would not have enough energy to overcome the work function?
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    (Original post by medicapplicant)
    alright i put Brittle and said it would snap without any noticeable yield but i dont know if the explanation i put was right :/
    Yeah I put it would snap easily I'm sure 2/2!
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    (Original post by medicapplicant)
    yh i guess, i think you're right, how many marks do you i would lose for timesing it by 3 (1mark ?)
    I have no idea bro, hopefully not many probably just the 1
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    What did you guys get for that rotatory disk thing?
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    What did people get for the first two questions about the momentum?
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    (Original post by RKM21)
    Thechocolate melty things were nodes. Not antinodes.
    No they werent, if they were nodes the H2O molecules in the chocolate wouldnt vibrate and so there would be no heating?
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    for the last two questions i got

    Anti Neutron -> Anti Proton + Position(e+) + Electron Neutrino(Ve)
    and Weak interaction
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    (Original post by ravioliyears)
    Same here!!
    Nodes are points of zero displacement
    If the particles on the wave dont move then how can the chocolate heat up?
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    does anyone do model answers??
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    https://youtu.be/3HZIrJtA6jc In case anyone wanted one i made it
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    (Original post by HasanRaza1)
    No they werent, if they were nodes the H2O molecules in the chocolate wouldnt vibrate and so there would be no heating?
    That's what i thought. Surely it must be an antinode otherwise the chocolate would absorb no waves
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    (Original post by monoman)
    The wavelength wasn't 12. It was actually 6cm because use need the of one wave not the 3


    Posted from TSR Mobile
    Yes i got 59×10^-3 m for wavelength
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    Name:  ImageUploadedByStudent Room1464087910.729445.jpg
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    Got something along these lines... Is this right?


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    Because there were 3 antinodes I thought that there would be four nodes (even tho that wouldn't have fit lol), so even though I put my final answer as 3x10^8/0.12 I thought that the wavelength was 0.08 and wrote 3x10^8/0.08 as well... Did anyone else do that?
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    (Original post by kiwifruit99)
    Name:  ImageUploadedByStudent Room1464087910.729445.jpg
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    Got something along these lines... Is this right?


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    I think that's right ( I put wavelength as 11.8 cm though)
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    (Original post by kiwifruit99)
    Name:  ImageUploadedByStudent Room1464087910.729445.jpg
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    Got something along these lines... Is this right?


    Posted from TSR Mobile
    Isn't that only half wavelength if you look at just the full line not the dotted line?
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    Any guesses for grade boundries
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    (Original post by MattyBrightman)
    Isn't that only half wavelength if you look at just the full line not the dotted line?
    Yeah he multiplied it by 2
 
 
 
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