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# 2016 Official AQA New Spec AS Level Physics Paper 1 - 24th of May 2016 watch

1. (Original post by kierans99)
What did you guys get for the stopping potential of the photoelectrons. I got like 1.4*10^-19J for the one before it asked for the stopping potential and then on that question it was only mark so I just put 1.4v?
for the stopping potential I got 0.88v
2. For the stopping potential. You had to use maximum kinetic energy= eV
1.4*10-19/1.6x10-19= 0.875
Two sf 0.90volts
3. (Original post by 11234)
What did people get for the percentage change in diameter. Did anyone get 0.79%
I got 21% decrease
4. (Original post by haza01)
I measured 59mm how was it 11.8cm???

Posted from TSR Mobile
59 X 2 = 118 You measure the distance from one node to the other which is only one half of a wavelength I think
5. (Original post by Hariss)
for the stopping potential I got 0.88v

Was it one sig fig or 2 i first had 0.875 then put it to 0.90
6. (Original post by Pouh)
Was it one sig fig or 2 i first had 0.875 then put it to 0.90
Is there much difference between the old and new spec?
7. What did everyone get for the reduction in diameter?? 25%??
8. (Original post by Pra99)
Does anyone have the paper?
yeah, in my pocket.

let me get it out
9. (Original post by HasanRaza1)
What did everyone get for the reduction in diameter?? 25%??
I got 0.79
10. [QUOTE=Pra99;65115641]Is there much difference between the old and new spec?[/QUOTE

Quite a handful of difference, they are more strict on sig figs and the the content is more about application i think, my teacher but apart from that ....
11. What did people get for the last electricity where the battery had internal r
12. Hey guys, first post in this thread, quick question...

Did anyone else find the whole paper relatively forgiving except for the electricity questions?

(Also, ticking a box for a final question made me smile)
13. To work out decelaration did you have to find the resultant force using the risistive forces and force already known then use this in f= ma, which gives you -10. Is this right?
14. (Original post by Pouh)
For the stopping potential. You had to use maximum kinetic energy= eV
1.4*10-19/1.6x10-19= 0.875
Two sf 0.90volts
two sf is 0.88.
the first 0 doesn't count
15. (Original post by BainesyA)
Hey guys, first post in this thread, quick question...

Did anyone else find the whole paper relatively forgiving except for the electricity questions?

(Also, ticking a box for a final question made me smile)
Yes, what did you get for the one with the voltmeter placed between A and B
16. For the choloclate bar question it melted at each antinode
you have to remember the stationary wave is unpolarised
the wavelength was i believe 11.7/11.8
I made a dumb mistake and wrote it as 10^-3 instead of 10^-2 when converting into metres. Anyone know how many marks i would lose????
17. (Original post by Pouh)
To work out decelaration did you have to find the resultant force using the risistive forces and force already known then use this in f= ma, which gives you -10. Is this right?
I got 2.7
18. [QUOTE=Pouh;65115755]
(Original post by Pra99)
Is there much difference between the old and new spec?[/QUOTE

Quite a handful of difference, they are more strict on sig figs and the the content is more about application i think, my teacher but apart from that ....
Is it harder though?
19. (Original post by Laceypr82)
I forgot that....I got wavelength as 120mm. How many marks would I lose
The answer is 120 not 80 because you have the distance between the antibodies not the the nodes. The distance between 2 nodes is half a wavelength and the distance between 2 anti nodes is the same as between 2 nodes so it's also half a wavelength[/QUOTE]

It's alright being a Jack of all trades, but not if you're a master of none
20. Does anyone reckon boundaries will go up

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