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2016 Official AQA New Spec AS Level Physics Paper 1 - 24th of May 2016 watch

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    (Original post by 11234)
    Is it wrong?
    I don't have a clue, but if we go by probability, there are more wrong answers than right answers. So probability says its wrong, but it made sense in my head.

    For both our sakes I hope it isn't wrong
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    (Original post by BainesyA)
    I put the following, or something along these lines.

    As the emf across the circuit is equal to sum of the emf of the individual components, then by replacing the battery with a with one of the same emf, but internal resistance, the voltmeter would read the same value.

    (Cant actually remember what the question was, if you remind me I can write what I actually answered)
    Question was
    1.5v battery is replaced with one with significant internal resistance. explain why the value on the voltmemter at A and B doesnt change
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    Was there multiple choice for this paper???
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    (Original post by Gurkin)
    What did people get for the last electricity where the battery had internal r
    Do you mean the one where you had to work out of one of the resistors? Like 0.15 I think. Or the voltmeter one, where I said that the resistor is in parallel and the reciprocal of a big number is very small and so it would have little difference
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    (Original post by BainesyA)
    I put the following, or something along these lines.

    As the emf across the circuit is equal to sum of the emf of the individual components, then by replacing the battery with a with one of the same emf, but internal resistance, the voltmeter would read the same value.
    I put that the internal resistance would reduce the terminal potential difference but the potential difference between the two points would be the same as the external arrangement of the resistances is the same therefore the voltage across each component will be less but the difference between A and B the same
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    (Original post by Person18)
    Do you mean the one where you had to work out of one of the resistors? Like 0.15 I think. Or the voltmeter one, where I said that the resistor is in parallel and the reciprocal of a big number is very small and so it would have little difference
    The one where thd voltmeter was placed between point a and b
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    (Original post by Pra99)
    Was there multiple choice for this paper???
    No thats paper 2. Which one do you reckon will have higher boundaries
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    (Original post by syns994)
    Question was
    1.5v battery is replaced with one with significant internal resistance. explain why the value on the voltmemter at A and B doesnt change
    I refer you to the point you quoted, I answered the right question, so the one you quoted is the answer I put, or along those lines
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    (Original post by 11234)
    No thats paper 2. Which one do you reckon will have higher boundaries
    I didn't do the test, but I'm assuming paper 1 as its meant to be easier.
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    (Original post by SaltandSugar)
    I put that the internal resistance would reduce the terminal potential difference but the potential difference between the two points would be the same as the external arrangement of the resistances is the same therefore the voltage across each component will be less but the difference between A and B the same
    I said something about the potential drops would be the same is that right
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    (Original post by SaltandSugar)
    I put that the internal resistance would reduce the terminal potential difference but the potential difference between the two points would be the same as the external arrangement of the resistances is the same therefore the voltage across each component will be less but the difference between A and B the same
    I put very similar to this but i had no idea it was a complete guess
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    (Original post by SaltandSugar)
    I put that the internal resistance would reduce the terminal potential difference but the potential difference between the two points would be the same as the external arrangement of the resistances is the same therefore the voltage across each component will be less but the difference between A and B the same
    I said that, the pd reading between A and B should be zero as there are no components in parallel to it
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    harder or easier than specimen paper lol I have biology and chemistry soon so im wondering whether this can inform a little?
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    (Original post by Chickenslayer69)
    where da unofficial markscheme
    its in my pocket, let me get it out for you.....

    chicken wings
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    Are we all sure the grade boundaries will be lower than last year? Last year was the lowest it's been.
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    (Original post by Gurkin)
    damn, i said the voltage would just be zero because it's in parallel with no components. But, wouldnt the voltmeter not record the emf as its not in paralel with the cell

    The question asked why the volmeter would read the same.
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    (Original post by LivToBe)
    The question asked why the volmeter would read the same.
    Yeah, zero before with no internal r,zero after with Ir
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    (Original post by Kraixo)
    Guys what did you pick for the meterial of the wires?

    I picked BC
    I pick B and C too
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    (Original post by 11234)
    What did people get for the percentage change in diameter. Did anyone get 0.79%
    I got 0.79 as well
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    (Original post by Gurkin)
    Yeah, zero before with no internal r,zero after with Ir
    Why zero? wasnt there 4 resistors in total or something and they were difference along each parallel branch?
 
 
 
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