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# Official OCR New Spec AS Level Physics: Depth in physics - 9th of May watch

1. I got 83J for the initial kinetic energy
2. (Original post by mahmzo)
Hey i used 30. I got a value of 30.7. Is that correct
I think it just depends on which one you used, but that should be correct if the working is; I just hope they took this into account :P.
3. (Original post by malihb123)
yeah I think I did the exact same as you
As who?
4. (Original post by akpai22)
As who?
I just worked back from ur answer and that means ur original velocity was 32.2ms^-1 and I don't know how you got that. Since that means ur horizontal velocity was 31.58ms^-1.
5. I got 31.5ms^-1 as my horizontal velocity because I used 0.57s instead of 0.6s
6. (Original post by Parhomus)
I just worked back from ur answer and that means ur original velocity was 32.2ms^-1 and I don't know how you got that. Since that means ur horizontal velocity was 31.58ms^-1.
It said to show that the time was about 0.6s so I usd the more accurate time of 0.57s and I got my values.
7. (Original post by akpai22)
It said to show that the time was about 0.6s so I usd the more accurate time of 0.57s and I got my values.
I got 0.64 by using v=u+at by I'm guessing you used S=ut+1/2at^2 which is rather interesting. The funny thing is both are correct but the reason they are different is probs because the value we got for the initial velocity was probably a rounded value.
8. (Original post by Parhomus)
I got 0.64 by using v=u+at by I'm guessing you used S=ut+1/2at^2 which is rather interesting. The funny thing is both are correct but the reason they are different is probs because the value we got for the initial velocity was probably a rounded value.
Will I be marked down for getting that answer do you think?
9. (Original post by akpai22)
Will I be marked down for getting that answer do you think?
I don't think there is much reason to assume you're incorrect; although most people in know used the v=u+at because s=ut+1/2at^2 also gives you an answer of t=0.7 something.
10. (Original post by Parhomus)
I don't think there is much reason to assume you're incorrect; although most people in know used the v=u+at because s=ut+1/2at^2 also gives you an answer of t=0.7 something.
Yeah that's true. God dammit I have mad a few errors now, I hope that I don't get below an A, will be really pissed off if I do get below an A.
11. I put 5.7 (x10^3) as my answer for the gradient, will I get the marks?
12. (Original post by akpai22)
Yeah I got 1.24x10^-19
How many marks do you think I would lose if I left it in eV?
13. (Original post by mxixbl)
I put 5.7 (x10^3) as my answer for the gradient, will I get the marks?
There will be a range. I got 5.8. If you answer makes sense and reflects on the line you drew you should get all ft marks
14. I think the only thing that OCR messed up with this paper was that they had a lot of questions where it was a show that and then lead onto another question; so it was hard to know which value to know to use. :c
15. (Original post by mahmzo)
There will be a range. I got 5.8. If you answer makes sense and reflects on the line you drew you should get all ft marks
I know that but I mean the fact that I put x10^-3 in the brackets
16. (Original post by GCSEsThen)
No its 2% because you can measure to +/- 0.5 mm not +/- 1mm
no because 2% is the percentage error for L whereas they want the error for L^2 so you double it - 4%
17. (Original post by elisha.marsh)
no because 2% is the percentage error for L whereas they want the error for L^2 so you double it - 4%
Oh my god you people trigger me so hard; just look at when I posted please :c.
18. (Original post by Parhomus)
Oh my god you people trigger me so hard; just look at when I posted please :c.
oh my god I'm so sorry i triggered you, i forgot being polite isn't a necessity online
19. (Original post by elisha.marsh)
oh my god I'm so sorry i triggered you, i forgot being polite isn't a necessity online
I wasn't referring to people being polite; I was referring to the fact that multiple people have said this and I already gave an answer.
20. For the question that asked for proof I did:

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