A smooth ball of mass 0.1kg is projected from ground level over smooth horizontal ground with an initial speed of 65 ms^-1 at an angle of a to the horizontal, where tan(a)=3/4. the coefficient of restitution between the ball and the ground is 0.4
I) show that the ball leaves the ground after the first bounce with a speed of 52ms^-1 in the horizontal direction and 15.6ms^-1 in the vertical direction. explain your reasoning carefully
II) Calculate the impulse on the ball at its first bounce.
The ball is in the air for T1 seconds between projection and bouncing the first time, T2 seconds between the first and second bounces and Tn seconds between the (n-1)th and nth bounces
III) show that T1=39/5 and Tn = 39/5 *(0.4)^(n-1)
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Please help me with my M2 impulse and momentum question watch
- Thread Starter
- 23-03-2016 17:42
- Official Rep
- 25-03-2016 19:03
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