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# Edexcel A2 D2 Mathematics June 2016 - Official Thread watch

1. (Original post by Historygcse)
I got that. Was the final solution optimal?
yes because all my improvement indices were positive
2. (Original post by anonymous2410)
What did you guys get for the profit of the last question? i got 900 something
£5550. total revenue - total costs (minimum cost was £1700 for the dynamic programming)
3. (Original post by Historygcse)
I got that. Was the final solution optimal?
Yes
4. For the question on game theory when it asked you to formulate it as a linear programming problem (the question before you had to put it in the simplex) did it say write your answer as inequalities or equalities??
5. (Original post by 8752)
£5550. total revenue - total costs (minimum cost was £1700 for the dynamic programming)
werent there two costs? one for material and the other was time

1. Classical - each vertex only visited once, practical - vertices can be revisited
Nearest neighbour lengths - 158 and 149
Lower bound = 86 (RMST) + 27 (Shortest arcs from A) = 113
113<optimal<=149

2. Initial flow = 59
C1 = 72
C2 = 86
New flow = 62, Cut = 62 so maximum due to minimum cut = maximum flow theorem

3. Alexa - 2, Ewan - 4, Faith - 1, cant remember - 3
maximum score = 248

4. Pivot row = R1
P+13....-5s=27
P=5s......
increasing s would increase P so not optimal

5. ....

6. Row minimums = ..... Row maximin = 0
Column maximums = ...... Column minimax = 4
0=/=4 so Row maximin =/= Column minimax so not stable

Let p1 be the probability with which A plays 1, p2 be the probability with which A plays 2 and p3 be the probability with which A plays 3 with p1,p2,p3>=0

Let v be the value of the original game to A
Let V=v+5 be the value of the new game to A

Maximise P-V=0

Subject to V - ...... + r = 0
V - ...... + r = 0
V - ...... + s = 0
V - ...... + t = 0
p1 + p2 + p3 + u = 1

7. Cost = 1700, 3,3,5,5,3
Profit = 5550
7. (Original post by 8752)
For the question on game theory when it asked you to formulate it as a linear programming problem (the question before you had to put it in the simplex) did it say write your answer as inequalities or equalities??
It said equalities
8. (Original post by anonymous2410)
werent there two costs? one for material and the other was time
Yes. total revenue = (19*700)=13300
Total cost of material= (200*19)= 3800
Total cost for time= (5*450)=2250
Minimum cost for production in the previous questio= 1700
total revenue-all the costs above=5550
9. (Original post by lukejoshjames)
For the optimal length in question 1, the boundaries were 113 and 158 right?
It was 149
10. (Original post by 8752)
Yes. total revenue = (19*700)=13300
Total cost of material= (200*19)= 3800
Total cost for time= (5*450)=2250
Minimum cost for production in the previous questio= 1700
total revenue-all the costs above=5550
yeah you are right, i got that wrong
11. (Original post by anonymous2410)
Yes
And was your most negative improvement index -2 after you worked out the first set of shadow costs. So before you found the second theta value to be 11 in the second iteration , did u get the most negative improvment index to be -2
12. (Original post by anonymous2410)
yeah you are right, i got that wrong
I copied the answer from the table wrong for the last question so I wrote 2000 instead of 1700 by accident. How many marks would I lose for that

Also for the profit part I used 2000 instead of 7000 so would I get 1/2 or 0/2?

Posted from TSR Mobile
13. (Original post by Themathgeek)
I copied the answer from the table wrong for the last question so I wrote 2000 instead of 1700 by accident. How many marks would I lose for that

Also for the profit part I used 2000 instead of 7000 so would I get 1/2 or 0/2?

Posted from TSR Mobile
You should only drop 4 for part a and 1 for part b in my opinion
14. on 6 how do u make the simplex tableau??? i just left it blank because i didn't know how to do it lmao
15. And was your most negative improvement index -2 after you worked out the first set of shadow costs. So before you found the second theta value to be 11 in the second iteration , did u get the most negative improvment index to be -2
17. (Original post by Will_R_9999)
It was 149 you little ***** boy
Mate calm down
18. What was the most negative improvement index in part b? Was it -2?
19. I failed that dynamic question
20. (Original post by Historygcse)
What was the most negative improvement index in part b? Was it -2?
I got a -3, can anyone agree?

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