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    (Original post by Historygcse)
    I got that. Was the final solution optimal?
    yes because all my improvement indices were positive
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    (Original post by anonymous2410)
    What did you guys get for the profit of the last question? i got 900 something
    £5550. total revenue - total costs (minimum cost was £1700 for the dynamic programming)
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    (Original post by Historygcse)
    I got that. Was the final solution optimal?
    Yes
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    For the question on game theory when it asked you to formulate it as a linear programming problem (the question before you had to put it in the simplex) did it say write your answer as inequalities or equalities??
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    (Original post by 8752)
    £5550. total revenue - total costs (minimum cost was £1700 for the dynamic programming)
    werent there two costs? one for material and the other was time
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    My answers:

    1. Classical - each vertex only visited once, practical - vertices can be revisited
    Nearest neighbour lengths - 158 and 149
    Lower bound = 86 (RMST) + 27 (Shortest arcs from A) = 113
    113<optimal<=149

    2. Initial flow = 59
    C1 = 72
    C2 = 86
    New flow = 62, Cut = 62 so maximum due to minimum cut = maximum flow theorem

    3. Alexa - 2, Ewan - 4, Faith - 1, cant remember - 3
    maximum score = 248

    4. Pivot row = R1
    P+13....-5s=27
    P=5s......
    increasing s would increase P so not optimal

    5. ....

    6. Row minimums = ..... Row maximin = 0
    Column maximums = ...... Column minimax = 4
    0=/=4 so Row maximin =/= Column minimax so not stable

    Let p1 be the probability with which A plays 1, p2 be the probability with which A plays 2 and p3 be the probability with which A plays 3 with p1,p2,p3>=0

    Let v be the value of the original game to A
    Let V=v+5 be the value of the new game to A

    Maximise P-V=0

    Subject to V - ...... + r = 0
    V - ...... + r = 0
    V - ...... + s = 0
    V - ...... + t = 0
    p1 + p2 + p3 + u = 1

    7. Cost = 1700, 3,3,5,5,3
    Profit = 5550
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    (Original post by 8752)
    For the question on game theory when it asked you to formulate it as a linear programming problem (the question before you had to put it in the simplex) did it say write your answer as inequalities or equalities??
    It said equalities
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    (Original post by anonymous2410)
    werent there two costs? one for material and the other was time
    Yes. total revenue = (19*700)=13300
    Total cost of material= (200*19)= 3800
    Total cost for time= (5*450)=2250
    Minimum cost for production in the previous questio= 1700
    total revenue-all the costs above=5550
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    (Original post by lukejoshjames)
    For the optimal length in question 1, the boundaries were 113 and 158 right?
    It was 149
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    (Original post by 8752)
    Yes. total revenue = (19*700)=13300
    Total cost of material= (200*19)= 3800
    Total cost for time= (5*450)=2250
    Minimum cost for production in the previous questio= 1700
    total revenue-all the costs above=5550
    yeah you are right, i got that wrong
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    (Original post by anonymous2410)
    Yes
    And was your most negative improvement index -2 after you worked out the first set of shadow costs. So before you found the second theta value to be 11 in the second iteration , did u get the most negative improvment index to be -2
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    (Original post by anonymous2410)
    yeah you are right, i got that wrong
    I copied the answer from the table wrong for the last question so I wrote 2000 instead of 1700 by accident. How many marks would I lose for that

    Also for the profit part I used 2000 instead of 7000 so would I get 1/2 or 0/2?



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    (Original post by Themathgeek)
    I copied the answer from the table wrong for the last question so I wrote 2000 instead of 1700 by accident. How many marks would I lose for that

    Also for the profit part I used 2000 instead of 7000 so would I get 1/2 or 0/2?



    Posted from TSR Mobile
    You should only drop 4 for part a and 1 for part b in my opinion
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    on 6 how do u make the simplex tableau??? i just left it blank because i didn't know how to do it lmao
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    And was your most negative improvement index -2 after you worked out the first set of shadow costs. So before you found the second theta value to be 11 in the second iteration , did u get the most negative improvment index to be -2
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    Grade boundary opinions?
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    (Original post by Will_R_9999)
    It was 149 you little ***** boy
    Mate calm down
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    What was the most negative improvement index in part b? Was it -2?
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    I failed that dynamic question
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    (Original post by Historygcse)
    What was the most negative improvement index in part b? Was it -2?
    I got a -3, can anyone agree?
 
 
 
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