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    By eliminating the arbitary constant A find the first order differential equation that is equiavalent to y^2=Ax
    Ive so far got 2ydy/dx= A
    I dont know what to do next
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    (Original post by rshah702)
    By eliminating the arbitary constant A find the first order differential equation that is equiavalent to y^2=Ax
    Ive so far got 2ydy/dx= A
    I dont know what to do next
    Well you know that A = \frac{y^2}{x} so if you plug this into your DE: 2y \frac{dy}{dx} = \frac{y^2}{x} now simplify.
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    Thank you
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    This question is wanted in the same format as before x^2+y^2=A does A get eliminated when differentiated. Btw what exam brd do you do
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    (Original post by rshah702)
    This question is wanted in the same format as before x^2+y^2=A does A get eliminated when differentiated. Btw what exam brd do you do
    Yeah, it does.

    Edexcel.
 
 
 
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