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    help me please
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    (Original post by sakurafall)
    help me please
    Have a think about what (x^2 + 3)^{-a} differentiates to.
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    Equivalently, if the above doesn't help then consider the sub u = x^2 + 3
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    (Original post by sakurafall)
    help me please
    (Original post by Gregorius)
    Have a think about what (x^2 + 3)^{-a} differentiates to.
    (Original post by Zacken)
    Equivalently, if the above doesn't help then consider the sub u = x^2 + 3
    i am interested in this, i don't know how to do this but i'm very intrigued...
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    (Original post by thefatone)
    i am interested in this, i don't know how to do this but i'm very intrigued...
    It's of the form \int f'(x) f(x)^{n} \, \mathrm{d}x
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    (Original post by Zacken)
    It's of the form \int f'(x) f(x)^{n} \, \mathrm{d}x
    so i need to differentiate this? what would i do?(if this is C3+ then i haven't done this yet, but it won't hurt to learn it now xD)
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    (Original post by thefatone)
    so i need to differentiate this? what would i do?(if this is C3+ then i haven't done this yet, but it won't hurt to learn it now xD)
    When you differentiate f(x)^{n+1} you get (n+1)f'(x)f(x)^{n} so if you're integrating f'(x)f(x)^n you get \frac{f(x)^{n+1}}{n+1} + c
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    (Original post by Zacken)
    When you differentiate f(x)^{n+1} you get (n+1)f'(x)f(x)^{n} so if you're integrating f'(x)f(x)^n you get \frac{f(x)^{n+1}}{n+1} + c
    oh yea of course that makes sense
    so when we integrate it do we just leave it in that form? in a fraction +C?
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    (Original post by thefatone)
    oh yea of course that makes sense
    so when we integrate it do we just leave it in that form? in a fraction +C?
    Yes.
 
 
 
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