Turn on thread page Beta
    • Thread Starter
    Offline

    2
    ReputationRep:
    Hi,

    I don't understand the last part of part C, and how you get the final part of the answer.

    Quick help is appreciated.
    Attached Images
      
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by TheKevinFang)
    Hi,

    I don't understand the last part of part C, and how you get the final part of the answer.

    Quick help is appreciated.
    \displaystyle H+\left[2e^2H\times \frac{1}{1-e^2}\right] = \frac{H(1-e^2)}{1-e^2} + \frac{2He^2}{1-e^2} = \frac{H-He^2 + 2He^2}{1-e^2} = ,,,
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by notnek)
    \displaystyle H+\left[2e^2H\times \frac{1}{1-e^2}\right] = \frac{H(1-e^2)}{1-e^2} + \frac{2He^2}{1-e^2} = \frac{H-He^2 + 2He^2}{1-e^2} = ,,,
    Sorry I don't understand what this is trying to show?
    • Thread Starter
    Offline

    2
    ReputationRep:
    https://onedrive.live.com/redir?resi...nt=photo%2cJPG

    This question, I'm also getting (1+2e/1-e) x (2h/g)^1/2? Why is it (1+e/1-e) x (2h/g)^1/2???
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by TheKevinFang)
    Sorry I don't understand what this is trying to show?
    I'm showing how they derived \displaystyle \frac{H(1+e^2)}{1-e^2}. I'll finish it off if you like:

    \displaystyle H+\left[2e^2H\times \frac{1}{1-e^2}\right] = \frac{H(1-e^2)}{1-e^2} + \left[\frac{2He^2}{1-e^2}\right] = \frac{H-He^2 + 2He^2}{1-e^2}

    \displaystyle = \frac{H+He^2}{1-e^2}= \frac{H(1+e^2)}{1-e^2}
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: March 28, 2016

2,581

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should predicted grades be removed from the uni application process
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.