Turn on thread page Beta

AQA A2 MFP2 Further Pure 2 – 24th June [Exam Discussion Thread] watch

    Offline

    17
    ReputationRep:
    (Original post by C0balt)
    What was 3b about that everyone's talking about?
    I believe it was the evaluation of s (the arc length).
    For anyone wondering how it was done, you could simply decompose into partial fractions or do what I did and add and subtract 2 in the numerator.
    Offline

    14
    ReputationRep:
    (Original post by IrrationalRoot)
    I believe it was the evaluation of s (the arc length).
    For anyone wondering how it was done, you could simply decompose into partial fractions or do what I did and add and subtract 2 in the numerator.
    Ah right, I was about to panic but I did partial fraction in the end haha
    Offline

    7
    ReputationRep:
    That was a pretty fun paper, must admit.
    Offline

    1
    ReputationRep:
    1) A=4,
    50/609

    2) beta = 1-2i,
    alpha*beta = 5,
    gamma = 1/3,
    P=-7, Q=-5

    3) -3/4 + ln7

    4) root3*pi / 18

    5) Modulus = 8,
    Locus is a circle centred at (-4root3, 4) radius 4, arg(w) = 2pi/3
    z = 2e^i*theta where theta = -7pi/18, 5pi/18, 17pi/18

    6) ln(2/3)
    3arcosh(2) + 6root3 + 5

    7)
    (Original post by IrrationalRoot)
    If anyone wants to know how the induction went:(1+p)^1 \geq 1+p obviously, so base case established.Assume (1+p)^k \geq 1+kp. Clearly we need to multiply by 1+p and we can do so without changing the sign of the inequality because p\geq -1\Rightarrow 1+p \geq 0.Therefore (1+p)^{k+1} \geq (1+kp)(1+p)=1+p+kp+kp^2=1+(k+1)p  +kp^2 \geq 1+(k+1)p, since p^2 \geq 0, k \geq 1 \Rightarrow kp^2 \geq 0.Therefore result holds for n=k+1 and by induction we have result.
    8) itan(3pi/8), itan(5pi/8), itan(7pi/8)
    tan2(pi/8)tan2(3pi/8) = 1
    tan2(pi/8) + tan2(3pi/8) = 6
    Offline

    3
    ReputationRep:
    What UMS would 55 marks get me?

    Fairly easy paper generally with quite a few impossible questions mixed in, I thought.
    • Community Assistant
    Offline

    20
    ReputationRep:
    Community Assistant
    Fair paper but I didnt answer like 14 mark; no proof, missed out the last 8 marks and couldnt integrate the fraction with x squared fully. Probs got a nice B
    • Thread Starter
    Offline

    6
    ReputationRep:
    (Original post by bencurnow)
    1) A=4,
    50/609

    2) beta = 1-2i,
    alpha*beta = 5,
    gamma = 1/3,
    P=-7, Q=-5

    3) -3/4 + ln7

    4) root3*pi / 18

    5) Modulus = 8,
    Locus is a circle centred at (-4root3, 4) radius 4, arg(w) = 2pi/3
    z = 2e^i*theta where theta = -7pi/18, 5pi/18, 17pi/18

    6) ln(2/3)
    3arcosh(2) + 6root3 + 5

    7)

    8) itan(3pi/8), itan(5pi/8), itan(7pi/8)
    tan2(pi/8)tan2(3pi/8) = 1
    tan2(pi/8) + tan2(3pi/8) = 6
    There's an unofficial MS out btw
    http://www.thestudentroom.co.uk/show....php?t=4184065
    [SIZE=1]
    Offline

    1
    ReputationRep:
    how many marks was the proof by induction?
    Offline

    14
    ReputationRep:
    (Original post by fffffg1g1)
    how many marks was the proof by induction?
    Six
    Offline

    20
    ReputationRep:
    was x=ln(2/3) definitely the root?
    Offline

    14
    ReputationRep:
    What UMS would 67 give me?
    Offline

    7
    ReputationRep:
    (Original post by C0balt)
    What UMS would 67 give me?
    93-97 probably.
    Offline

    14
    ReputationRep:
    (Original post by student0042)
    93-97 probably.
    Hopefully 90s...
    Offline

    14
    ReputationRep:
    (Original post by C0balt)
    Hopefully 90s...
    Well there's no point trying to over analyse your exam when you have others left to do.
    Offline

    1
    ReputationRep:
    (Original post by C0balt)
    What UMS would 67 give me?
    Last year that was the 100 cap and imo this paper was harder and more people will have lost larger chunks of marks
    Offline

    14
    ReputationRep:
    (Original post by MrMagic12345)
    Last year that was the 100 cap and imo this paper was harder and more people will have lost larger chunks of marks
    Well I found last year's harder apart from induction but I was less prepared when I did the mock so maybe you're right. Oh well. Onto M2 now haha
    Offline

    2
    ReputationRep:
    can anyone remember the limits for the 1+x^2/1-x^2? thanks
    Offline

    7
    ReputationRep:
    (Original post by Jm098)
    can anyone remember the limits for the 1+x^2/1-x^2? thanks
    0 and 3/4 I think
    Offline

    11
    ReputationRep:
    Thought it was a very nice paper, surprisingly. I agree on all the posted answers.
    Offline

    2
    ReputationRep:
    (Original post by A Slice of Pi)
    Thought it was a very nice paper, surprisingly. I agree on all the posted answers.
    What'd you think o 'the induction? (broken keyboard)
 
 
 
The home of Results and Clearing

1,770

people online now

1,567,000

students helped last year

University open days

  1. SAE Institute
    Animation, Audio, Film, Games, Music, Business, Web Further education
    Thu, 16 Aug '18
  2. Bournemouth University
    Clearing Open Day Undergraduate
    Fri, 17 Aug '18
  3. University of Bolton
    Undergraduate Open Day Undergraduate
    Fri, 17 Aug '18
Poll
Do you want your parents to be with you when you collect your A-level results?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.