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# AQA A2 MFP3 Further Pure 3 – 18th May 2016 [Exam Discussion Thread] watch

1. (Original post by Hjyu1)
Thanks for that, you feeling ready for the exams?
Mostly, need to do some last minute revision but as I said earlier, FP3 is one of my better modules

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2. (Original post by TheLifelessRobot)
Here are the grade boundaries for FP3 for 100ums, a* and a from jan 2010.
Thanks for this, will add this to the OP

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3. Anyone here doing fp4? Is there a thread for that I can't find one.
4. Need help on June 12 paper question 8 bi and c ANYONE HELP???
5. (Original post by misslili118)
Need help on June 12 paper question 8 bii and c ANYONE HELP???
What have you tried?
6. (Original post by misslili118)
Need help on June 12 paper question 8 bii and c ANYONE HELP???
For bii, try substituting r=4root2 into the expression given at the start of b, then solve for theta

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7. (Original post by jjsnyder)
For bii, try substituting r=4root2 into the expression given at the start of b, then solve for theta
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SORRY I meant bi not bii ( finding the closest to pole O ) and also part c
8. (Original post by misslili118)
SORRY I meant bi not bii ( finding the closest to pole O ) and also part c

I couldnt get the last part, it just destroyed my brain and I think my working for bi) is right not too sure tbf
9. (Original post by Hjyu1)

I couldnt get the last part, it just destroyed my brain and I think my working for bi) is right not too sure tbf
Working for bi is correct, I'll do c now

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10. (Original post by misslili118)
SORRY I meant bi not bii ( finding the closest to pole O ) and also part c
Here is the working for c, I spent a while looking at the best method to explain it. It is not an easy question, so I apologise if the solution is confusing, let me know if you have any questions

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11. Anyone know where I can find more difficult polar coordinate questions that are similar to the Aqa ones?
12. (Original post by Hjyu1)
Anyone know where I can find more difficult polar coordinate questions that are similar to the Aqa ones?
Go on the C3 15th june thread and there is a link there for legacy papers and find the ones called something like map-5, there are some tough questions there if you skim through those papers
13. (Original post by Qcomber)
Go on the C3 15th june thread and there is a link there for legacy papers and find the ones called something like map-5, there are some tough questions there if you skim through those papers

Thank you
14. (Original post by jjsnyder)
here is the working for c, i spent a while looking at the best method to explain it. It is not an easy question, so i apologise if the solution is confusing, let me know if you have any questions

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thank you omg
15. (Original post by hjyu1)

i couldnt get the last part, it just destroyed my brain and i think my working for bi) is right not too sure tbf
thank you so much
16. (Original post by jjsnyder)
Here is the working for c, I spent a while looking at the best method to explain it. It is not an easy question, so I apologise if the solution is confusing, let me know if you have any questions

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I converted the co-ordinates of P, N and Q into Cartesian and used length of lines for PN, NQ and QP to find out the angle using cosine rule. Would I still get the marks?

17. Does anyone mind explaining why we have to get rid of the minus sign in part biii)
18. (Original post by TheLifelessRobot)
I converted the co-ordinates of P, N and Q into Cartesian and used length of lines for PN, NQ and QP to find out the angle using cosine rule. Would I still get the marks?
Yeah that's fine, it would still get you all the marks and would be included in the more detailed mark scheme that examiners get, but it would take longer of course.

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19. (Original post by Hjyu1)

Does anyone mind explaining why we have to get rid of the minus sign in part biii)
What did you get for the value of 6ii?

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20. (Original post by Hjyu1)

Does anyone mind explaining why we have to get rid of the minus sign in part biii)
The limits used for part bii are not the limits that are used to evaluate biii. The limits for part bii actually switch to calculate biii. They should be 0 (upper) and 1 (lower) instead of 1 (upper) and 0 (lower). This is because of the substitution; when you change the limits for the substitution using y=1/x, you calculate y=1/infinity = 0 for the upper and y=1/1 = 1 for the lower. If you calculate the integral again using the limits 0, 1 instead of 1, 0 the sign changes and becomes positive. You'd get 0 - -1/2 = 1/2 instead of -1/2 - 0 = -1/2 for the definite integral.

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