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AQA A2 MFP3 Further Pure 3 – 18th May 2016 [Exam Discussion Thread] Watch

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    (Original post by JDMason)
    1. Ae^5x/2 - 2x - 4/5

    2. 5/3, 8/5

    3. Approximation: 2.081, 2.080

    4. c=36, d=20, traslate 4 across

    5. 0.5x^2 +3x +ln(x+1) +1

    6. 1/36

    7. I got my constants wrong but I believe this is correct: y= 2cos2x - 1/2(e^pi)sin2x + 1/2(e^4x) + xSin2x - 2xcos2x

    8. (1/2)ln3 - 1/2

    roast me
    Got all the same answers except for p and q, but I think I got that wrong. I think you should post this as unofficial ms. 😃
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    I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
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    (Original post by IrrationalRoot)
    I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
    They're changing everything because they ****ing hate us.
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    The unnoficial answers posted seem all correct, I will append them to the first post later
    I made some silly errors but nothing content wise, just arithmetic slips :/


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    For the very last question, the area one:

    Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
    ??

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    I got something along the lines of y= 0.5x^2 +3x -ln(X+1) +cx -(2+C)ln(X+1) +2cln(X+1) + B is this along the right lines, I had noticed a similar answer on the thread but without the two constants? Were there constraints that I failed to spot?
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    (Original post by Barbecuetime123)
    I got something along the lines of y= 0.5x^2 +3x -ln(X+1) +cx -(2+C)ln(X+1) +2cln(X+1) + B is this along the right lines, I had noticed a similar answer on the thread but without the two constants? Were there constraints that I failed to spot?
    What question was this?
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    What was question number 5?
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    (Original post by Adam_98)
    For the very last question, the area one:

    Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
    ??

    Posted from TSR Mobile
    This is what I did, got something like .5ln(3) -.5
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    (Original post by Adam_98)
    For the very last question, the area one:

    Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
    ??

    Posted from TSR Mobile
    (1+tanX)^2 mate, you gotta square it in polar. also half it

    but otherwise I think so yeah
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    (Original post by Xzielon)
    What question was this?
    5 I think, where u = y' abd you had to make a subs.
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    (Original post by Barbecuetime123)
    5 I think, where u = y' abd you had to make a subs.
    I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
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    (Original post by Xzielon)
    I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
    Once I made the substitution, I used an integrating factor and then integrated both sides as normal for u, then integrated to get y. Not sure why my answer was so messed up, I had to do a bit of nasty manipulating to be able to integrate too.
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    (Original post by Barbecuetime123)
    Once I made the substitution, I used an integrating factor and then integrated both sides as normal for u, then differentiated to get y. Not sure why my answer was so messed up, I had to do a bit of nasty manipulating to be able to integrate too.
    I wanted to use the integrating factor but I wasn't sure if I should. I thought that's a way to go but it would make it messy so I kept thinking about an easier way and time run out as I wanted to try it for the sake of it.
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    (Original post by Xzielon)
    I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
    basically what I did:

    sub in u and du/dx for dy/dx and d2y/dx2

    get integrating factor using partial fractions integral (I got the reciprocal of the RHS bit)

    integrate 1 and solve how you would an integrating factor one

    sub u back out so you get dy/dx = a load of crap

    then you have some horrible shite to integrate and you had to rewrite it as x+3+1/(x+1) I think it was, something like that

    then you have equation, sub in 0 to find constant value

    I got what everyone else got, y = x^2/2 + 3x + ln(x+1) +1
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    Let's just hope the grade boundaries are like, 20 marks for an A :'(
    Flopped too hard, I got all positives for question 1, question 2 can't remember, done half of question 4 and flopped 6. Missed out the 4 marker for question 8 :'(
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    (Original post by Mop3476)
    basically what I did:

    sub in u and du/dx for dy/dx and d2y/dx2

    get integrating factor using partial fractions integral (I got the reciprocal of the RHS bit)

    integrate 1 and solve how you would an integrating factor one

    sub u back out so you get dy/dx = a load of crap

    then you have some horrible shite to integrate and you had to rewrite it as x+3+1/(x+1) I think it was, something like that

    then you have equation, sub in 0 to find constant value

    I got what everyone else got, y = x^2/2 + 3x + ln(x+1) +1
    Can you remember the original equation? I wanna try what I planned to do
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    (Original post by Adam_98)
    For the very last question, the area one:

    Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
    ??

    Posted from TSR Mobile
    what value of theta at b did you get?
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    (Original post by IrrationalRoot)
    I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
    That **** didn't even tell us how many Qs there were...
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    anyone know the allocation of marks for all parts of the questions if i remember right it was something like
    1a. 3
    b. 3

    2a. 1
    b. 4

    3a. 6
    b. 3
    c. 3
    ci. 1

    4. 5

    5a. 1
    b. 11

    6a. 3
    b. 4

    7. 10

    8a. 3
    b. 4
    c. 3
    d. 7
 
 
 
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