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    I'm stuck on q 5 on the OCR November 2002 paper. here's the question:
    An object P of mass 0.2kg hangs by a string from a point O of the roof of a lorry. The lorry is moving horizontally with constant acceleration a m/s^2 and the string makes a constant angle of 8 degrees with the vertical. Find
    i) the tension in the string
    ii) the value of a

    anybody know how to answer this???
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    (Original post by SI 1)
    I'm stuck on q 5 on the OCR November 2002 paper. here's the question:
    An object P of mass 0.2kg hangs by a string from a point O of the roof of a lorry. The lorry is moving horizontally with constant acceleration a m/s^2 and the string makes a constant angle of 8 degrees with the vertical. Find
    i) the tension in the string
    ii) the value of a

    anybody know how to answer this???
    Resolving forces vertically, you know that Tcos(8) = 0.2g, as there is no acceleration in this direction (forces up = forces down). Then resolve horizontally using F = ma. Does this help?
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    Here's the diagram for the question
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    (Original post by ombtom)
    Resolving forces vertically, you know that Tcos(8) = 0.2g, as there is no acceleration in this direction (forces up = forces down). Then resolve horizontally using F = ma. Does this help?
    Yup. Thank you!!!
 
 
 
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