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    Here is a link to the question: http://prntscr.com/amgop5
    I had a bit of trouble with this question, so what I deduced from increasing the charge by 50% is that the energy E must also increase in turn, as seen in this equation E = 1/2QV, so am I right in saying that the voltage V is constant and should remain unaffected by the increase of the charge? However I do not understand how the value of energy is is 2.25 E? The correct answer is C by the way. Thanks in advance!
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

    You can also find the Exam Thread list for A-levels here and GCSE here. :dumbells:


    Just quoting in Puddles the Monkey so she can move the thread if needed
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    Q = CV so p.d. is proportional to Q.
    If charge is increased by a half that is a factor of 1.5 that V will increase by
    E = ½ QV = ½ CV2 = ½ Q2/CE is proportional to Q2
    If charge is increased by a half that is a factor of 1.5 so energy will increase by 1.52 = 2.25
 
 
 
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