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    http://filestore.aqa.org.uk/subjects...1-QP-JUN14.PDF

    help pls
    question 3c
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    lambda = h/mv
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    (Original post by Kyx)
    lambda = h/mv
    so i have v=\dfrac{h}{mv}
    then
    v=\dfrac {6.63 \times 10^{-34}}{\left( 9.11 \times 10^{-31} \times 207 \right) \times 2.9 \times 10^{-9}}
     v=1200ms^{-1}

    thanks
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    (Original post by thefatone)
    so i have v=\dfrac{h}{mv}
    then
    v=\dfrac {6.63 \times 10^{-34}}{\left( 9.11 \times 10^{-31} \times 207 \right) \times 2.9 \times 10^{-9}}
     v=1200ms^{-1}

    thanks
    np

    although it's lambda equals, not v equals
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    (Original post by thefatone)
    so i have v=\dfrac{h}{mv}
    then
    v=\dfrac {6.63 \times 10^{-34}}{\left( 9.11 \times 10^{-31} \times 207 \right) \times 2.9 \times 10^{-9}}
     v=1200ms^{-1}

    thanks
    Or can say velocity is propotional to 1/m, so if m is 207 times as big can multiply velocity in question by 1/207. Same thing just less chance of making an algebraic error, and not dependent on any rounding you might have done earlier
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    (Original post by Kyx)
    np

    although it's lambda equals, not v equals
    oops that's supposed to be rearranged

    v=\dfrac{h}{m\lambda}
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    (Original post by thefatone)
    oops that's supposed to be rearranged

    v=\dfrac{h}{m\lambda}
    I thought so
 
 
 
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