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    • Thread Starter

    Here are the links to the question:
    Part 1: http://prntscr.com/amtyqc
    Part 2: http://prntscr.com/amtz1j

    I've worked out part one by just doing the following calculation to work out the time period, time/no. of oscillations, this had given me a value of :
    2.8 Seconds

    Right, now the second part I was confused by; it is asking us to calculate the kinetic energy as she passed through the lowest point, at this point velocity is max and displacement is zero right? So I calculated Vmax with 2*Pi*f*A, which had given me 0.56 m/s and plugged this value into Ek = 1/2*m*v^2 which then had given me 2.83J. However this was incorrect as the mark scheme stated to work out the kinetic energy all that was required was to equate mgh=1/2*m*v^2, where 'h' in this case was the given amplitude, I just don't understand why my approach was incorrect.
    •  Official Rep

     Official Rep
    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

    You can also find the Exam Thread list for A-levels here and GCSE here. :dumbells:

    Just quoting in Puddles the Monkey so she can move the thread if needed
    (Original post by Puddles the Monkey)
Do you agree with the PM's proposal to cut tuition fees for some courses?

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