Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    13
    ReputationRep:
    https://e4c57ffe72e64565dd23ce74ff8c.../Resolving.pdf

    I don't understand part b (ii) of the first question. How would you draw the force diagram and which is the resultant force when F is vertical? Every time I try to draw it, I end up getting the wrong answer because I use Tan(theta) = Opp/Aj but according to the mark scheme, you should use Cos(theta) = Adj/Hyp.... but I don't understand why.
    Offline

    22
    ReputationRep:
    (Original post by jessyjellytot14)
    https://e4c57ffe72e64565dd23ce74ff8c.../Resolving.pdf

    I don't understand part b (ii) of the first question. How would you draw the force diagram and which is the resultant force when F is vertical? Every time I try to draw it, I end up getting the wrong answer because I use Tan(theta) = Opp/Aj but according to the mark scheme, you should use Cos(theta) = Adj/Hyp.... but I don't understand why.
    You're talking about b(ii), that's just resolving the tension vertically. There's a 30^{\circ} degree angle between the tension and the vertical, so resolving the tension in the vertical direction gives you T \cos 30^{\circ}.
    Offline

    16
    ReputationRep:
    (Original post by jessyjellytot14)
    https://e4c57ffe72e64565dd23ce74ff8c.../Resolving.pdf

    I don't understand part b (ii) of the first question. How would you draw the force diagram and which is the resultant force when F is vertical? Every time I try to draw it, I end up getting the wrong answer because I use Tan(theta) = Opp/Aj but according to the mark scheme, you should use Cos(theta) = Adj/Hyp.... but I don't understand why.
    I just basically drew up what Zacken said, along with a little explanation to how we find horizontal and vertical components when the force acts at an angle

    Offline

    22
    ReputationRep:
    (Original post by KaylaB)
    I just basically drew up what Zacken said, along with a little explanation to how we find horizontal and vertical components when the force acts at an angle

    That's very neat! :love:
    Offline

    16
    ReputationRep:
    (Original post by Zacken)
    That's very neat! :love:
    Thank you

    Spoiler:
    Show
    it took more attempts than I care to admit for it to reach that standard
    Offline

    22
    ReputationRep:
    (Original post by KaylaB)
    Thank you
    Spoiler:
    Show
    it took more attempts than I care to admit for it to reach that standard
    Mine never has and I've done a lot of maths. :rofl:
    • Thread Starter
    Offline

    13
    ReputationRep:
    (Original post by KaylaB)
    I just basically drew up what Zacken said, along with a little explanation to how we find horizontal and vertical components when the force acts at an angle

    Oh wow thank you for taking the time to draw it out ! In the triangle you drew would y represent the weight force?
    Offline

    18
    ReputationRep:
    (Original post by KaylaB)
    I just basically drew up what Zacken said, along with a little explanation to how we find horizontal and vertical components when the force acts at an angle

    X
    Whoa that drawing
    • Thread Starter
    Offline

    13
    ReputationRep:
    (Original post by Zacken)
    You're talking about b(ii), that's just resolving the tension vertically. There's a 30^{\circ} degree angle between the tension and the vertical, so resolving the tension in the vertical direction gives you T \cos 30^{\circ}.
    Thanks, I would rep you but it won't let me
    Offline

    22
    ReputationRep:
    (Original post by jessyjellytot14)
    Thanks, I would rep you but it won't let me
    Don't worry about it.

    y would represent the horizontal component of the tension, nothing more.
    Offline

    16
    ReputationRep:
    (Original post by jessyjellytot14)
    Oh wow thank you for taking the time to draw it out ! In the triangle you drew would y represent the weight force?
    (Original post by Zacken)
    Don't worry about it.

    y would represent the horizontal component of the tension, nothing more.

    Yeah exactly, y is the horizontal component of the tension. I just labelled it y so that you could work out what it could be using the triangle, which is T \sin 30^{\circ}


    (Original post by Student403)
    Whoa that drawing
    It's one of the only things I'm good for in mechanics :innocent:
    Offline

    18
    ReputationRep:
    (Original post by KaylaB)
    Yeah exactly, y is the horizontal component of the tension. I just labelled it y so that you could work out what it could be using the triangle, which is T \sin 30^{\circ}




    It's one of the only things I'm good for in mechanics :innocent:
    Fair enough - I'm sure you're good at the content too :lol:
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brussels sprouts
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.