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    I don't know how to solve the equation : e^t/8 = 1000e^-t/8
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    Have you covered the addition rule for logarithms?
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    (Original post by Sinfire)
    Have you covered the addition rule for logarithms?
    Yes...oh I know what to do now! Lol
    Thanks
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    (Original post by Oliviazh)
    Yes...oh I know what to do now! Lol
    Thanks
    No prob
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    You could multiply through by  e^{-t/8} to form a quadratic.
    Then if you're unsure of what to do from there make the substitution  u=e^{t/8} .
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    (Original post by B_9710)
    You could multiply through by  e^{-t/8} to form a quadratic.
    Then if you're unsure of what to do from there make the substitution  u=e^{t/8} .
    In this case it isn't a quadratic.
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    (Original post by EricPiphany)
    In this case it isn't a quadratic.
    Why not?
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    (Original post by Zacken)
    Why not?
    Isn't that overcomplicating things? Can't you just multiply through by e^t/8 and take the natural log.
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    (Original post by EricPiphany)
    Isn't that overcomplicating things? Can't you just multiply through by e^t/8 and take the natural log.
    Well, yeah. That's what I'd do. But it's always good to know of alternate solutions. :yep:
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    (Original post by Zacken)
    Well, yeah. That's what I'd do. But it's always good to know of alternate solutions. :yep:
    I suppose you're right
 
 
 
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