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    Hey guys I was doing some revision for logs and struggled to understand the answer for this question and seem to get it wrong after trying multiple times. Any help would be much appreciated! Thanks!

    Question: Given the simultaneous equation
    2^x( power of x)=3^y
    x+y=1

    Show that x=log3/log6
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    (Original post by Basdemraj)
    Hey guys I was doing some revision for logs and struggled to understand the answer for this question and seem to get it wrong after trying multiple times. Any help would be much appreciated! Thanks!

    Question: Given the simultaneous equation
    2^x( power of x)=3^y
    x+y=1

    Show that x=log3/log6
    Take logs of the first equation. You then simply have a standard pair of simultaneous equations to solve.
    x+y=1, \quad x\log(2)=y\log(3).
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    (Original post by joostan)
    Take logs of the first equation. You then simply have a standard pair of simultaneous equations to solve.
    x+y=1, \quad x\log(2)=y\log(3).
    Thank you
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    (Original post by Basdemraj)
    Thank you
    It will probably be worth noting that:
    a+\dfrac{b}{c}=\dfrac{ac+b}{c}.
 
 
 
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