x Turn on thread page Beta
 You are Here: Home >< Maths

1. ...
2. then use the log division:

ln8^2 +ln(10^2/5)
ln8^2 +ln20
6ln2 +ln20

you could simplify further i suppose, it depends what form they ask..
3. ...
4. (Original post by Sam00)
would ln8^2 - ln5 + ln10^2 therefore be the same as ln64 - ln5 + ln100

therefore ln64 - ln100/5

therefore ln64 - ln20? :s
No

maybe it will be clearer if I use brackets,

its this:

2ln(8) - ln(5) + 2ln(10)
ln(8^2) - ln(5) + ln(10^2)
ln(8^2) + [ln(10^2) - ln(5)] (just rearranged it and put brackets on whats important)

[If you subtract two logs you just divide whats inside the log]

so now:

ln64 + ln[(10^2)/(5)]

ln(64) + ln(20)

Often in simplification we try to make the numbers as small as possible so we can write:

ln(2^6) + ln(20)
6ln(2) + ln(20)
5. (Original post by Sam00)
...
What was the point of this?

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: April 4, 2016
Today on TSR

### Four things top students are doing

Over the Easter break

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams