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    A crane is raising a load of 500 tonnes at a steady rate of 5 cm/s. what power is the engine of the crane producing?
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    (Original post by monika16)
    A crane is raising a load of 500 tonnes at a steady rate of 5 cm/s. what power is the engine of the crane producing?
    P=Fv

    The unit of v is ms^{-1} so you have a unit conversion to do. If the load weighs 500 tones, what force is being exerted against gravity?
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    Alternatively, the GPE gained in one second is  (0.05\times 500000g) \text{J} . And power = work done/time.
    This just gives a different way of thinking about it but in reality it is exactly the same as the method shown above.
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    (Original post by Kvothe the arcane)
    P=Fv

    The unit of v is ms^{-1} so you have a unit conversion to do. If the load weighs 500 tones, what force is being exerted against gravity?
    To see why both are equivalent: P = \frac{\text{Work done}} { \text{time} } = \frac{Fs}{t} = F\frac{s}{t} = Fv.
 
 
 
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