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    This may seem simple but my head wont get around it so
    1. Write 9^3 x 27^2 as a single power of 3
    2. Write 8^6 / 4^3 x 2^5 as a single power of 2

    Please could you answer this thank you
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    Bit late for maths?
    Well for these questions, to simplify them you need a common base. So work out what 9 is in terms of 3 and how that can apply to your problem, using rules of indices. Then do the same for the 27, and use the other indice rule where you multiply two together
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    Probably didn't make any sense but I'm tired aha
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    yeah for the first one you basically have to do:

    9^3 = (3^2)^3
    27^2 = (3^3)^2

    so you do:

    (3^2)^3 x (3^3)^2
    = 3^12
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    (Original post by Ninja360)
    This may seem simple but my head wont get around it so
    1. Write 9^3 x 27^2 as a single power of 3
    2. Write 8^6 / 4^3 x 2^5 as a single power of 2

    Please could you answer this thank you
    For the second one: \displaystyle \frac{(2^3)^6}{(2^2)^3 \times 2^5}
 
 
 
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