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Can anyone help me with this physics question and explain it? Watch

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    I hope everyone can see both images above which are from a question from an aqa physics paper, as-level. I don't get how to do 6b, the answers on the first page are right but the table on the second I can't complete. please can someone work it out and help me! Thanks
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    Remember: at a junction, the current that is in the circuit before is equal to the current in the circuit after. That means that the current gets split between the two paths it can take.

    I'm not sure about the p.d though...
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    (Original post by stevenp99)
    Name:  image.jpg
Views: 107
Size:  496.6 KB
    Attachment 519845519847

    I hope everyone can see both images above which are from a question from an aqa physics paper, as-level. I don't get how to do 6b, the answers on the first page are right but the table on the second I can't complete. please can someone work it out and help me! Thanks
    Im pretty sure you use ratios
 
 
 
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