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    Hi do anyone know anything about this quote. how can one minus minus be one, Some said its linguistically correct, but i dont know how, can anyone can help me with this ?




    "Your formulas are ever running correct,
    but in my calcuation,one minus one is always one.



    THanks
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    (Original post by ahyolmu)
    Hi do anyone know anything about this quote. how can one minus minus be one, Some said its linguistically correct, but i dont know how, can anyone can help me with this ?




    "Your formulas are ever running correct,
    but in my calcuation,one minus one is always one.



    THanks
    im not sure if your quote is right, because that can never be true.
    however one minus minus one can be one.

    its not saying 1 -- 1
    because that would be 2

    it is saying ONE -(-1)
    as in, you have one -(-1)
    which IS one.
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    x = y => x^2 = xy => x^2 - y^2 = xy - y^2 => (x+y)(x-y)=y(x-y) => x + y = y => 2y = y => 2 = 1 => 1 - 1 = 2 - 1 = 1 QED

    Aren't I hilarrrrrrrious :rolleye: LOL
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    (Original post by fishpaste)
    x = y => x^2 = xy => x^2 - y^2 = xy - y^2 => (x+y)(x-y)=y(x-y) => x + y = y => 2y = y => 2 = 1 => 1 - 1 = 2 - 1 = 1 QED

    Aren't I hilarrrrrrrious :rolleye: LOL
    been drinking, mr paste?
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    (Original post by fishpaste)
    x = y => x^2 = xy => x^2 - y^2 = xy - y^2 => (x+y)(x-y)=y(x-y) => x + y = y => 2y = y => 2 = 1 => 1 - 1 = 2 - 1 = 1 QED

    Aren't I hilarrrrrrrious :rolleye: LOL
    The old division by zero trick...I love it. You can prove anything is equal to anything else.
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    "Your formulas are ever running correct,
    but in my calcuation,one minus one is always one.



    Lol... one anything is always one... one sheep is one, one cow is one, one paintbrush is one, one minus one is always one (minus one).

    You shorten the sentence because usually it's obvious, but in this case this leads to ambiguity.

    That's what I think.
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    (Original post by mik1a)
    "Your formulas are ever running correct,
    but in my calcuation,one minus one is always one.



    Lol... one anything is always one... one sheep is one, one cow is one, one paintbrush is one, one minus one is always one (minus one).

    You shorten the sentence because usually it's obvious, but in this case this leads to ambiguity.

    That's what I think.
    I actually thought that the phrase in this case, "one minus one" was actually minus one - Because it was treating the "minus one" as an object and hence the "one" prior to it as a count.
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    (Original post by Checkey)
    I actually thought that the phrase in this case, "one minus one" was actually minus one - Because it was treating the "minus one" as an object and hence the "one" prior to it as a count.
    mm great two minus eight is two , three minus seven is three..etc how clever ..
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    this is stupid BUT
    he said calculation

    so 1x -1 is not 1 (even though there is just one object), it is -1.

    however! 1x -(-1) IS 1, as i was saying.
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    (Original post by kikzen)
    this is stupid BUT
    he said calculation

    so 1x -1 is not 1 (even though there is just one object), it is -1.

    however! 1x -(-1) IS 1, as i was saying.
    Yes, I agree.
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    (Original post by kikzen)
    this is stupid BUT
    he said calculation

    so 1x -1 is not 1 (even though there is just one object), it is -1.

    however! 1x -(-1) IS 1, as i was saying.
    You're wrong. This quote refers to numbers being considered as objects. One basket is always one. One apple is always one. In the same way, One (minus one) is always one.
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    (Original post by Yannis)
    You're wrong. This quote refers to numbers being considered as objects. One basket is always one. One apple is always one. In the same way, One (minus one) is always one.
    In other words, one object (of type == 'minus one') is one (object).
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    OK-

    Let 1=-1-(-1)-(-1) and -1=2-2-1

    therefore 1-1 = -1-(-1)-(-1)+2-2-1
    ...................= -2 -(-1)+2
    ...................= 1

    Surprised no-one got that

    Thank you

    Stu Isaacs
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    (Original post by Yannis)
    You're wrong. This quote refers to numbers being considered as objects. One basket is always one. One apple is always one. In the same way, One (minus one) is always one.
    i understand that, but because he said calculation and not count (or something similar) that cant be right. plus in the message he wrote something about minus minus...
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    (Original post by Stuart Isaacs)
    OK-

    Let 1=-1-(-1)-(-1) and -1=2-2-1

    therefore 1-1 = -1-(-1)-(-1)+2-2-1
    ...................= -2 -(-1)+2
    ...................= 1

    Surprised no-one got that

    Thank you

    Stu Isaacs
    That's wrong. The second last line does not follow from the previous.
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    (Original post by fishpaste)
    x = y => x^2 = xy => x^2 - y^2 = xy - y^2 => (x+y)(x-y)=y(x-y) => x + y = y => 2y = y => 2 = 1 => 1 - 1 = 2 - 1 = 1 QED

    Aren't I hilarrrrrrrious :rolleye: LOL
    i'm prolly not even getting the joke... but from

    x + y = y how can he get

    2y = y
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    (Original post by fishpaste)
    x = y => x^2 = xy => x^2 - y^2 = xy - y^2 => (x+y)(x-y)=y(x-y) => x + y = y => 2y = y => 2 = 1 => 1 - 1 = 2 - 1 = 1 QED

    Aren't I hilarrrrrrrious :rolleye: LOL
    Very good fishpaste! xxxniceguy - the first line says x=y so he's just replacing x with y

    How about this then - it's weirder than just dividing by zero (ie I have no idea where the problem is, maybe principal roots or something?) Anyway:

    i = sqrt(-1) so i^2 = -1
    i^2 = ii = sqrt(-1)*sqrt(-1) = sqrt[(-1)*(-1)]
    but (-1)*(-1) = 1 so i^2 = sqrt(1) = 1 so 1 = -1 :confused:
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    (Original post by Bezza)
    Very good fishpaste! xxxniceguy - the first line says x=y so he's just replacing x with y

    How about this then - it's weirder than just dividing by zero (ie I have no idea where the problem is, maybe principal roots or something?) Anyway:

    i = sqrt(-1) so i^2 = -1
    i^2 = ii = sqrt(-1)*sqrt(-1) = sqrt[(-1)*(-1)]
    but (-1)*(-1) = 1 so i^2 = sqrt(1) = 1 so 1 = -1 :confused:
    root1 is both -1 and 1
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    (Original post by keithy)
    root1 is both -1 and 1
    But I'm using the principal roots all the way through and √1 = 1
    i = √(-1) so i^2 = -1
    i^2 = ii = √(-1)*√(-1) = √[(-1)*(-1)]
    but (-1)*(-1) = 1 so i^2 = √1 = 1 so 1 = -1
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    (Original post by Bezza)
    But I'm using the principal roots all the way through and √1 = 1
    i = √(-1) so i^2 = -1
    i^2 = ii = √(-1)*√(-1) = √[(-1)*(-1)]
    but (-1)*(-1) = 1 so i^2 = √1 = 1 so 1 = -1

    Just because you're using principle roots doesn't mean you can just ignore that 1^2 = (-1)^2

 
 
 
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