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How to find the component of weight acting parallel to a slope? Watch

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    To get the answer you have to convert the mass into Newtons, then multiply that by Sin(5)

    But don't you do the hypotenuse*sin(x) when finding the opposite side? And mg isn't the hypotenuse anyway it is the opposite? This doesn't make sense to me as we are looking for something parallel to the slope, which would be the hypotenuse surely
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    Your answer is correct. You find (970*9.81)* sin(5).
    which does equal approx. 830N.

    The reason you are confused is because the hypotenuse here is the weight of the car acting downwards.
    Construct a right angled triangle using the weight as the hypotenuse.
    Sorry bout the crappy paint drawing but here is what you need.
    Spoiler:
    Show
    Then it is clearly what you said.
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    (Original post by The-Spartan)
    Your answer is correct. You find (970*9.81)* sin(5).
    which does equal approx. 830N.

    The reason you are confused is because the hypotenuse here is the weight of the car acting downwards.
    Construct a right angled triangle using the weight as the hypotenuse.
    Sorry bout the crappy paint drawing but here is what you need.
    https://gyazo.com/4045a46d2220367e26bef052e71413c3
    Then it is clearly what you said.
    That makes sense, thank you
 
 
 
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