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# Maths Trig Identities Help watch

1. Hi - can anyone explain how you do this to me? I have to root sin^2theta/sin theta divided by cos theta
But unsure where to go from there: It is Q8 on the attachment

Thanks for your help!
Attached Images

2. it is not entirely clear what your expression looks like... but it may cancel down to

√ ( tan θ )
3. uh could you write that out a little clearer please? Like, write down the problem using these:

sin^2 x

cos x
4. I think you cancel the sin^2theta/sin theta down to just sin theta, and then that divided by cos theta will give you tan theta but not 100% sure sorry!
5. (Original post by Shadowshock118)
Hi - can anyone explain how you do this to me? I have to root sin^2theta/sin theta divided by cos theta
But unsure where to go from there: It is Q8 on the attachment

Thanks for your help!
So, right off the bat: so that .

This means you have:

Moved to maths, by the way.
6. (Original post by sammyyrosee)
uh could you write that out a little clearer please? Like, write down the problem using these:

sin^2 x

cos x
I got to root sin^2 x/ sinx ÷ cosx
7. (Original post by Zacken)
So, right off the bat: so that .

This means you have:

Moved to maths, by the way.
Brilliant, thank you very much
8. (Original post by Shadowshock118)
I got to root sin^2 x/ sinx ÷ cosx
Yes, and .

Edit: because x is acute, obviously.

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