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    I was doing a GCSE practice booklet but it had no mark scheme, I was wondering if someone could clarify if my answers are correct?

    I got:

    a) 253m
    b) 046 (degrees)

    Thanks!

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    (Original post by chrlhyms)
    anyone?
    You got the first one right but the second one, ϑ = 45.81, you normally round angle degrees to two decimal places unless it says otherwise, you got all the right working out it seems.
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    a)
    BC^2 = 500^2 + 700^2 - 2 x 500 x 700 x Cos(15)
    BC^2 = 250,000 +490,000 - 676148.0784
    BC^2 = 63851.9216
    BC = 252.6893777
    BC = 253

    b)
    CosX = (252.68...^2 + 700^2 - 500^2) / (2 x 700 x 252.68...)
    CosX = 303851.9216 / 353765.1288
    X = Cos^-1 (0.8589086285)
    X = 30.80573627
    X + Y + 15 = 180
    Y = 134.1942637
    Y + Theta = 180
    Theta = 45.80573627
    Theta = 46

    Both Correct - Well done! Good Luck with your Maths exam!
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    (Original post by 10tojones)
    a)
    BC^2 = 500^2 + 700^2 - 2 x 500 x 700 x Cos(15)
    BC^2 = 250,000 +490,000 - 676148.0784
    BC^2 = 63851.9216
    BC = 252.6893777
    BC = 253

    b)
    CosX = (252.68...^2 + 700^2 - 500^2) / (2 x 700 x 252.68...)
    CosX = 303851.9216 / 353765.1288
    X = Cos^-1 (0.8589086285)
    X = 30.80573627
    X + Y + 15 = 180
    Y = 134.1942637
    Y + Theta = 180
    Theta = 45.80573627
    Theta = 46

    Both Correct - Well done! Good Luck with your Maths exam!
    Thank you so much!!!! we had the same workings out too, ahhh thanks so much for your help! have a nice day :-)
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    (Original post by one_man_abdullah)
    You got the first one right but the second one, ϑ = 45.81, you normally round angle degrees to two decimal places unless it says otherwise, you got all the right working out it seems.
    oh i see, thank you!!!!!
 
 
 
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