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    Hey.
    For Part 6 (iii). Im not sure how i meant to do the question such that i can "justify my answer fully". Whats the reason for this wording?
    thanks
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    I'm guessing you have to show that the horizontal component of the force is bigger than Fmax
    And so justify how that makes it move
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    (Original post by SamuelN98)
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    Hey.
    For Part 6 (iii). Im not sure how i meant to do the question such that i can "justify my answer fully". Whats the reason for this wording?
    thanks
    If the horizontal component is less than \mu R then friction will be enough to oppose motion i.e. the friction will be equal to the force.

    If the force is \geq \mu R then friction will have reached it's limit and so the frictional force will be equal to \mu R.
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    Mate I know how to do it lol
    The OP doesn't
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    (Original post by Sharaf371)

    Mate I know how to do it lol
    The OP doesn't
    Are you sure?

    (Original post by Sharaf371)

    I'm guessing you have to show that the horizontal component of the force is bigger than Fmax
    It's not bigger... it's smaller.

    And so justify how that makes it move
    It doesn't move, that's the whole point.

    We tend to be taught F = \mu R in mechanics - but the actual expression or formula is F \leq \mu R.
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    (Original post by Sharaf371)
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    Mate I know how to do it lol
    The OP doesn't
    Sorry - quoted the wrong person!
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    Posted from TSR Mobile

    (Original post by Zacken)
    Are you sure?



    It's not bigger... it's smaller.



    It doesn't move, that's the whole point.

    We tend to be taught F = \mu R in mechanics - but the actual expression or formula is F \leq \mu R.
    I haven't done the question so I was "guessing". Obviously if I did do it then I'd find if it was bigger or smaller. And so I would know it moves or not
 
 
 
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