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    My working our seems very different to the mark scheme, but I got the same exact answer. I'm just wondering if I will get the full marks. I would really appreciate if some of you could tell me if my answer will get the full 8 marks.


    Past paper: http://qualifications.pearson.com/co...e_20130513.pdf

    Mark scheme: http://qualifications.pearson.com/co...c_20130815.pdf


    My answer: http://www.mediafire.com/convkey/102...b33gye73zg.jpg


    Thanks
    Reda
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    (Original post by Reda2)
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    It's actually quite similar. That would get you full marks. Well done on the presentation and layout, it's very neat and readable; any examiner would be impressed!
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    (Original post by Zacken)
    It's actually quite similar. That would get you full marks. Well done on the presentation and layout, it's very neat and readable; any examiner would be impressed!

    Thank very much! I was just worried about the way I did the angel, I found alpha as a decimal and just used it that way.

    Thanks
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    (Original post by Reda2)
    Thank very much! I was just worried about the way I did the angel, I found alpha as a decimal and just used it that way.

    Thanks
    Nothing really wrong with that. You should practice using the "ANS" button on your caculator. If you'd found the angle by doing arctan whatever, the doing sine [ANS] would have gotten you an exact value and simplified your working considerably.
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    (Original post by Reda2)
    Thank very much! I was just worried about the way I did the angel, I found alpha as a decimal and just used it that way.

    Thanks
    The reason they give you \tan \alpha = \frac{3}{4} is so you can find \cos \alpha and \sin \alpha without having to use your calculator.

    Since \tan \alpha = \frac{3}{4}, you have a right-angled triangle with an acute angle \alpha, opposite length 3 and adjacent length 4. So the hypotenuse must be 5 and then working out \cos\alpha and \sin\alpha as fractions is simple.

    But you wouldn't lose a mark if you made sure you didn't round the calculator value.
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    (Original post by notnek)
    The reason they give you \tan \alpha = \frac{3}{4} is so you can find \cos \alpha and \sin \alpha without having to use your calculator.

    Since \tan \alpha = \frac{3}{4}, you have a right-angled triangle with an acute angle \alpha, opposite length 3 and adjacent length 4. So the hypotenuse must be 5 and then working out \cos\alpha and \sin\alpha as fractions is simple.

    But you wouldn't lose a mark if you made sure you didn't round the calculator value.

    Yes, I think I should get used to doing it that way, its also takes less time!
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    (Original post by Reda2)
    Yes, I think I should get used to doing it that way, its also takes less time!
    Draw a right angled triangle, it helps figure out exact ratios easily without the need for ugly irrational numbers.
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    Do you get full marks? You have the mark scheme right in front of you.

    Nice pen btw, where you get it from?
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    Impressive that you think it is paper and ink! Lol. I use the Surface Pro 4.
 
 
 
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