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# A2 physics aqa multiple choice Watch

1. This is the mark scheme answer to a question I have....

Acceleration = omega squared x radius = (omega squared x diameter ) / 2
So.... 2pi squared x diameter x frequency squared = a

My question is where does the division by 2 disappear ?
2. (Original post by HG1)
This is the mark scheme answer to a question I have....

Acceleration = omega squared x radius = (omega squared x diameter ) / 2
So.... 2pi squared x diameter x frequency squared = a

My question is where does the division by 2 disappear ?
Im guessing: (4pi squared x frequency squared x diameter) / 2 <---- that equation comes from subbing omega=2πf into omega squared
4 / 2, would get rid of the 2 on the bottom,
hence: 2pi squared x diameter x frequency squared = a

That's would I think anyways not 100% sure myself mate
3. (Original post by fisher96)
Im guessing: (4pi squared x frequency squared x diameter) / 2 <---- that equation comes from subbing omega=2πf into omega squared
4 / 2, would get rid of the 2 on the bottom,
hence: 2pi squared x diameter x frequency squared = a

That's would I think anyways not 100% sure myself mate

Yeah that makes perfect sense mate ! Thanks a lot , I just wasn't seeing it like that for some reason lol
4. (Original post by HG1)
Yeah that makes perfect sense mate ! Thanks a lot , I just wasn't seeing it like that for some reason lol
Distance between the 8nc and 2nc charges is 60mm
At a point between the charges, on the line joining them, the resultant electric field strength is zero. How far is this point from the + 8.0 nC charge?

Would you mind helping me with this question ?
5. (Original post by HG1)
Distance between the 8nc and 2nc charges is 60mm
At a point between the charges, on the line joining them, the resultant electric field strength is zero. How far is this point from the + 8.0 nC charge?

Would you mind helping me with this question ?
Which year paper is that? I've worked it out but gotta make sure I got the right answer lol
6. Ok, I've found the question and my answer was right.
There is a few ways to do this question, I'll list my method here:
So it's asking for the distance from the 8nc charge. Where Electric field = 0, this will be nearer the +2nc charge

Hope that image shows what I mean. Also we call the distance from the +8nc to this point "X" or whatever letter you want, and the distance therefore from the +2nc to that point is "60mm - X"
Attachment 521285521289
Hope that file up their also opens ^

You basically make the electric field of one equal the other. Then using some maths you can get the answer. I've written out what I did step by step, hope it makes sense.
Attached Images

7. (Original post by fisher96)
Ok, I've found the question and my answer was right.
There is a few ways to do this question, I'll list my method here:
So it's asking for the distance from the 8nc charge. Where Electric field = 0, this will be nearer the +2nc charge

Hope that image shows what I mean. Also we call the distance from the +8nc to this point "X" or whatever letter you want, and the distance therefore from the +2nc to that point is "60mm - X"
Attachment 521285521289
Hope that file up their also opens ^

You basically make the electric field of one equal the other. Then using some maths you can get the answer. I've written out what I did step by step, hope it makes sense.
Thank you so much much mate ! Such a great help I've Been trying to do this for ages lol

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