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# Calculating tension (materials) watch

1. An elastic cord of unstretched length 160mm has a cross sectional area of 0.64m^2. The cord is stretched to a length of 190mm. Assume that Hooke's law is obeyed for this range and that the cross sectional area remains constant.
The young modulus for the material of the cord = 2.0*10^7 Pa.

Calculate the tension in the cord at this extension.

I'm confused about what formulae I am meant to be using/how to apply them. I tried to do something by working out the stress and the strain, but I don't know how to get the answer.
Guidance is appreciated
2. Stress = Tension / Cross sectional area

Youngs modulous = stress / strain

You can find the strain by subtracting the extended length from the original length divided by the original length.

You already have the Youngs modulous, the cross sectional area and the lengths.

Very simple tbh.

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