hello everyone!

please could someone help me with this question?

In a particular area 30% of men and 20% of women are overweight and there are four men and three women working in an office there. Find the probabillity that there are 2 overweight people in the office.

if someone could just tell me how to go about it, i dont think i actually need to see the working, i just dont know what to do. i've already worked out the probability of 0, 1 or 2 overweight men and 0, 1 or 2 overweight women.

Thanks, rep available obviously

please could someone help me with this question?

In a particular area 30% of men and 20% of women are overweight and there are four men and three women working in an office there. Find the probabillity that there are 2 overweight people in the office.

if someone could just tell me how to go about it, i dont think i actually need to see the working, i just dont know what to do. i've already worked out the probability of 0, 1 or 2 overweight men and 0, 1 or 2 overweight women.

Thanks, rep available obviously

Jonquil

aha! thats what i thought! but how do i work out the prob of 1 fat man and 1 fat woman? do i multiply them or add them or what?

thank you james xxxxx

thank you james xxxxx

Multiply them. They're independent events.

James Gurung

I like the way we went from "overweight" to "fat"!

I won't inform the H&R crew if you won't.

Original post by Jonquil

hello everyone!

please could someone help me with this question?

In a particular area 30% of men and 20% of women are overweight and there are four men and three women working in an office there. Find the probabillity that there are 2 overweight people in the office.

if someone could just tell me how to go about it, i dont think i actually need to see the working, i just dont know what to do. i've already worked out the probability of 0, 1 or 2 overweight men and 0, 1 or 2 overweight women.

Thanks, rep available obviously

please could someone help me with this question?

In a particular area 30% of men and 20% of women are overweight and there are four men and three women working in an office there. Find the probabillity that there are 2 overweight people in the office.

if someone could just tell me how to go about it, i dont think i actually need to see the working, i just dont know what to do. i've already worked out the probability of 0, 1 or 2 overweight men and 0, 1 or 2 overweight women.

Thanks, rep available obviously

I'm struggling with finding the probability that there are 0 overweight men. I can't get the right fraction to use but I'm pretty sure its 7C0 (something)^0 (something)^7??

Original post by ndelfava

I'm struggling with finding the probability that there are 0 overweight men. I can't get the right fraction to use but I'm pretty sure its 7C0 (something)^0 (something)^7??

Don't know if the relevant information has been posted, but going on the original post and yours:

It is given that there are 4 men (of the seven), so for there to be 0 overweight men, you're interest in 4C0 (P man overweight)^0(P man not overweight)^4, or putting it more simply P(man not overweight)^4.

Original post by ndelfava

I'm struggling with finding the probability that there are 0 overweight men. I can't get the right fraction to use but I'm pretty sure its 7C0 (something)^0 (something)^7??

Where did you see this question from out of interest? It doesn’t feel like a question you’d see in a modern textbook

Original post by Notnek

Where did you see this question from out of interest? It doesn’t feel like a question you’d see in a modern textbook

AQA A Level Mathematics Year 1 (AS) (Aqa a Level As)

by Sophie Goldie, Susan Whitehouse , et al.

ISBN 9781510455580

(edited 4 years ago)

Original post by ghostwalker

AQA A Level Mathematics Year 1 (AS) (Aqa a Level As)

by Sophie Goldie, Susan Whitehouse , et al.

ISBN 9781510455580

by Sophie Goldie, Susan Whitehouse , et al.

ISBN 9781510455580

Thanks. That’s a new textbook although the question is slightly different. I wonder if “overweight” was replaced with “underweight”

Original post by Notnek

Thanks. That’s a new textbook although the question is slightly different. I wonder if “overweight” was replaced with “underweight”

My bad - didn't check the detail. Suspect you're correct; further digging produces a couple of volumes from around 2011 that use "overweight".

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