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Redox reactions

What are the steps for balancing a redox reaction?
I use this method always:
1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
2. Hydrogen (add H+ to balance Hydrogen atoms)
3. Charge (add electrons to make sure the charge is the same on each side)

Post any questions you are finding difficult.. :smile:
Reply 2
E(lectrons)
O(xygen)
H(hydrogen)
C(harge)

mnemonic EveryOne Hates Chemistry
Original post by haj101
I use this method always:
1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
2. Hydrogen (add H+ to balance Hydrogen atoms)
3. Charge (add electrons to make sure the charge is the same on each side)

Post any questions you are finding difficult.. :smile:


For the question:
image.jpeg
I used your method But I dint get the right answer

Can you go though the question step by step?
(edited 8 years ago)
image.jpg
Original post by haj101
I use this method always:
1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
2. Hydrogen (add H+ to balance Hydrogen atoms)
3. Charge (add electrons to make sure the charge is the same on each side)

Post any questions you are finding difficult.. :smile:


Did as last year wished the textbook could've explained as good as you :smile:
Original post by Shiv Loves Maths
Did as last year wished the textbook could've explained as good as you :smile:


Aw! thank you :colondollar:
Reply 7
1) balance the species having its oxidation state changed
2) balance the oxygens by adding waters
3) balance the hydrogens by adding H+
4) balance the charge by adding e- to the more +ve side

e.g. Cr2O72- -> Cr3+
1) Cr2O72- -> 2Cr3+
2) Cr2O72- -> 2Cr3+ + 7H2O
3) Cr2O72- + 14H+ -> 2Cr3+ + 7H2O
4) The LHS had 2- and 14+ i.e. 12+. The RHS has 6+. Add 6e- to the LHS, i.e. Cr2O72- + 14H+ +6e- -> 2Cr3+ + 7H2O
Original post by haj101
image.jpg


Thank you :smile:
Original post by fullmetal heart
Thank you :smile:


You're welcome, do ask if you have issues with anymore questions x

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