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    What are the steps for balancing a redox reaction?
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    I use this method always:
    1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
    2. Hydrogen (add H+ to balance Hydrogen atoms)
    3. Charge (add electrons to make sure the charge is the same on each side)

    Post any questions you are finding difficult..
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    E(lectrons)
    O(xygen)
    H(hydrogen)
    C(harge)

    mnemonic EveryOne Hates Chemistry
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    (Original post by haj101)
    I use this method always:
    1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
    2. Hydrogen (add H+ to balance Hydrogen atoms)
    3. Charge (add electrons to make sure the charge is the same on each side)

    Post any questions you are finding difficult..
    For the question:
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    I used your method But I dint get the right answer

    Can you go though the question step by step?
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    (Original post by haj101)
    I use this method always:
    1. Oxygen (number of oxygens should be same on each side- if not add water to balance them out)
    2. Hydrogen (add H+ to balance Hydrogen atoms)
    3. Charge (add electrons to make sure the charge is the same on each side)

    Post any questions you are finding difficult..
    Did as last year wished the textbook could've explained as good as you
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    (Original post by Shiv Loves Maths)
    Did as last year wished the textbook could've explained as good as you
    Aw! thank you
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    1) balance the species having its oxidation state changed
    2) balance the oxygens by adding waters
    3) balance the hydrogens by adding H+
    4) balance the charge by adding e- to the more +ve side

    e.g. Cr2O72- -> Cr3+
    1) Cr2O72- -> 2Cr3+
    2) Cr2O72- -> 2Cr3+ + 7H2O
    3) Cr2O72- + 14H+ -> 2Cr3+ + 7H2O
    4) The LHS had 2- and 14+ i.e. 12+. The RHS has 6+. Add 6e- to the LHS, i.e. Cr2O72- + 14H+ +6e- -> 2Cr3+ + 7H2O
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    (Original post by haj101)
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    Thank you
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    (Original post by fullmetal heart)
    Thank you
    You're welcome, do ask if you have issues with anymore questions x
 
 
 
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