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# Intergration by parts Watch

1. I have had a go at this question. I am trying to intergrate e^5y / 5 dy and I got e^5y / 25

Is this correct?
2. (Original post by ak1992)

I have had a go at this question. I am trying to intergrate e^5y / 5 dy and I got e^5y / 25

Is this correct?
No, you need to use IBP again on .

In general, to integrate w.r.t using IBP, you need to apply IBP times.
3. This is what I don't understand. To IBP again you would have to let one be U and the other be dv/dy.
Would you differentiate e^5y / 5 and intergrate the 2y?
4. (Original post by ak1992)
This is what I don't understand. To IBP again you would have to let one be U and the other be dv/dy.
Would you differentiate e^5y / 5 and intergrate the 2y?
No, you'd differentiate the 2y and integrate the e^5y.

5. Does this look about right?

Thank you for your help!

(Original post by Zacken)
No, you'd differentiate the 2y and integrate the e^5y.
6. (Original post by ak1992)

Does this look about right?

Thank you for your help!
Almost, it should be and not remember to distribute your negative signs. The rest is fine.

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