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Intergration by parts

ak1992

I have had a go at this question. I am trying to intergrate e^5y / 5 dy and I got e^5y / 25

Is this correct?

Reply 1

Zacken

Original post by ak1992

I have had a go at this question. I am trying to intergrate e^5y / 5 dy and I got e^5y / 25

Is this correct?

No, you need to use IBP again on

\int 2y e^{5y}/5 \, \mathrm{d}y

.

In general, to integrate

e^{ay}y^n

w.r.t

y

using IBP, you need to apply IBP

n

times.

Reply 2

ak1992

This is what I don't understand. To IBP again you would have to let one be U and the other be dv/dy.
Would you differentiate e^5y / 5 and intergrate the 2y?

Reply 3

Zacken

Original post by ak1992

This is what I don't understand. To IBP again you would have to let one be U and the other be dv/dy.
Would you differentiate e^5y / 5 and intergrate the 2y?