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    The question is,
    The 12th term of a arithmetic sequence is 35, The 17th term is four times the 2nd term, find the nth term


    i know i have to find A and D using simultaneus equations my 1st one is

    A+11d= 35

    but i dont know how to write my second one, how do i write the 17th term being four times the 2nd term?
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    (Original post by SunDun111)
    The question is,
    The 12th term of a arithmetic sequence is 35, The 17th term is four times the 2nd term, find the nth term


    i know i have to find A and D using simultaneus equations my 1st one is

    A+11d= 35

    but i dont know how to write my second one, how do i write the 17th term being four times the 2nd term?
    Well the second term is the first term plus the common difference.

    So A + 16d = 2(A + d)
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    (Original post by Zacken)
    Well the second term is the first term plus the common difference.

    So A + 16d = 2(A + d)
    wouldnt it be 4(A+D) because A+D = 2nd term, ?
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    (Original post by SunDun111)
    wouldnt it be 4(A+D) because A+D = 2nd term, ?
    Yep, it's just that I'm a bit blind and dumb and can't read properly.
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    (Original post by Zacken)
    Yep, it's just that I'm a bit blind and dumb and can't read properly.
    its fine man haha cheers for your help!
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    (Original post by SunDun111)
    its fine man haha cheers for your help!
    No worries.
 
 
 
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