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    Hey this may seem a stupid question but I can't seem to do question 1(iii) and 1(iv) of the june 2012 a2 empa task 1 any help would be appreciatedName:  2016-04-13 (5).png
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    What have you tried for part (iii)? Where have you got stuck rearranging the formula?

    In part (iv), you can write the equation in the form y=mx+c (general straight line), where y is the quantity on the vertical axis and x the quantity on the horizontal axis. You're giving those quantities in the question, so once you understand the concept that shouldn't be too hard. The next thing is to work out how you could determine R1 by considering the properties of the straight line.
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    Just to add onto part iii

    \displaystyle T_1=2\pi \sqrt{\frac{7(R_1-r)}{5g}} \iff T_1^2=4\pi^2 \frac{7(R_1-r)}{5g}

    Try solving this from there. Should be easy enough
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    \dfrac{T_1^2 \times 5g}{28\pi^2} + r = R_1

    Tut tut tut
    You have the values you need for the equation.
 
 
 
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