It's question 2b from the June 2010 series, AQA AS physics, "In a demonstration of Galileo’s investigation, the number of swings of a pendulum was used to time a trolley after it was released from rest. A block was positioned to mark the distance that the trolley had travelled after a chosen whole number of swings.
See Figure 2. The mass of the trolley in Figure 2 is 0.20 kg and the slope is at an angle of 1·8o to the
Show that the component of the weight acting along the slope is about 0.06 N." The mass of the trolley in Figure 2 is 0.20 kg and the slope is at an angle of 1·8o to the
Show that the component of the weight acting along the slope is about 0.06 N. " I can only get the first mark for working out that the weight of the trolley is 1.962N, but I don't understand how to draw the triangle to use SOHCAHTOA to get the force along the slope. The only way I get the answer is be drawing the triangle out weirdly and the mark scheme doesn't explain anything either. Can anyone explain how this question would be approached?
Help with this AS physics mechanics question? watch
- Thread Starter
- 16-04-2016 00:42
- Official Rep
- 18-04-2016 02:03
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Just quoting in Puddles the Monkey so she can move the thread if needed
Spoiler:Show(Original post by Puddles the Monkey)
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- TSR Community Team
- 18-04-2016 10:04
- 18-04-2016 13:05
Your approach is correct:
Try doing something like this (this is reversed but you get the idea)Spoiler:Where mg is your value for weight (1.962) and x is your angle of 1.8 degrees.Show
The component horizontal to the slope is mgsin(x) as shown, this is parallel.
You should now get the correct answer