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    It's question 2b from the June 2010 series, AQA AS physics, "In a demonstration of Galileo’s investigation, the number of swings of a pendulum was used to time a trolley after it was released from rest. A block was positioned to mark the distance that the trolley had travelled after a chosen whole number of swings.
    See Figure 2. The mass of the trolley in Figure 2 is 0.20 kg and the slope is at an angle of 1·8o to the
    horizontal.
    Show that the component of the weight acting along the slope is about 0.06 N." The mass of the trolley in Figure 2 is 0.20 kg and the slope is at an angle of 1·8o to the
    horizontal.
    Show that the component of the weight acting along the slope is about 0.06 N. " I can only get the first mark for working out that the weight of the trolley is 1.962N, but I don't understand how to draw the triangle to use SOHCAHTOA to get the force along the slope. The only way I get the answer is be drawing the triangle out weirdly and the mark scheme doesn't explain anything either. Can anyone explain how this question would be approached?
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

    You can also find the Exam Thread list for A-levels here and GCSE here. :dumbells:


    Just quoting in Puddles the Monkey so she can move the thread if needed
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    Your approach is correct:
    Try doing something like this (this is reversed but you get the idea)
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    Where mg is your value for weight (1.962) and x is your angle of 1.8 degrees.
    The component horizontal to the slope is mgsin(x) as shown, this is parallel.
    You should now get the correct answer
 
 
 
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