Part C is the one I don't understand.
How am I supposed to take AC = AB? Does it mean that the gradients are the same (well, considering the answer, no, but still)? The lines are the same? What is the question implying? I know that the lines would form an isosceles, but how am I supposed to know that just out of nothing?
How do I know that if line AB = AC, there'll be an isosceles? Watch
- Thread Starter
- 16-04-2016 21:34
- 16-04-2016 21:36
AC = AB just means the length of the lines are the same, not their gradients
- 17-04-2016 00:40
I'm not sure if you've completed this or not, but here's some help anyway!
From part b, you should have found that AB has length of root 41.
You do part C in a similar way. So, you know A is (7,4) and C is (2,t).
AC^2 = (t-4)^2 + (2-7)^2.
And you are given that AC = AB. So, AC is also equal to root 41.
So, ((root 41))^2 = (t-4)^2 + (2-7)^2.
Can you expand this for me and see what you get t as being?
Once you've done that, i'll help you with part d) if you need it.