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    p= (1/λ) / ( (1/λ)+(1/μ) ) -----> μ / (λ+μ)


    q= (1/μ) / ( (1/μ)+(1/λ) )------>λ / (λ+μ)


    can anyone tell from the original p and q statement to get those 2 finalised versions of each?


    Thanks





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    (Original post by djh-10)
    p= (1/λ) / ( (1/λ)+(1/μ) ) -----> μ / (λ+μ)


    q= (1/μ) / ( (1/μ)+(1/λ) )------>λ / (λ+μ)


    can anyone tell from the original p and q statement to get those 2 finalised versions of each?


    Thanks




    In each case, to start, turn the denominator into a single fraction.

    \dfrac{1}{\mu}+\dfrac{1}{\lambda  }=...


    Then remember that if you are dividing by a fraction, you turn it upside down, and multiply.

    See what you can do.
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    (Original post by djh-10)
    p= (1/λ) / ( (1/λ)+(1/μ) ) -----> μ / (λ+μ)


    q= (1/μ) / ( (1/μ)+(1/λ) )------>λ / (λ+μ)


    can anyone tell from the original p and q statement to get those 2 finalised versions of each?


    Thanks




    Get rid of the fractions on the numerator, and on the denominator.

    Eg. If you had (1/2) / (1/3) you would multiply both by 2, to give 1 / (2(1/3) and then multiply both top and bottom by 3 to give 3/2.

    Do the same thing but with your Lambda. Your question with Mu is exactly the same thing but with a Mu instead.
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    Got it now.

    Thanks folks!
 
 
 
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