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# Indicies watch

1. 3x^2/3= 6x

How to solve this?

What I did was divide by 3 to give me
X^2/3=2x
Now I'm stuck
2. (Original post by Ggffffhh)
3x^2/3= 6x

How to solve this?

What I did was divide by 3 to give me
X^2/3=2x
Now I'm stuck
i mean i got x=0 but i'm sure that's not the answer you're looking for xD
i'm stuck too

:/
Zacken
3. (Original post by Ggffffhh)
X^2/3=2x
Now I'm stuck
(Original post by thefatone)
i mean i got x=0 but i'm sure that's not the answer you're looking for xD
i'm stuck too

:/
Zacken
Simples: so either or the latter is easy to solve, since .
4. There is another solution as well as and that is . This comes from dividing by .
5. (Original post by Zacken)
Simples: so either or the latter is easy to solve, since .
oh this step caught me

i just took out the whole x xD and everything i knew about indices went out the window
6. (Original post by thefatone)
oh this step caught me

I think you mean x^{-\frac{1}{3}}, use the curly brackets.
7. (Original post by Bath~Student)
false..
Oh yeah? Elaborate.
8. (Original post by Zacken)
Oh yeah? Elaborate.
Not inherently incorrect.

But I feel your method is rather awkward.

Why not cube both sides, factor out an x^2 giving x^2 ( 8x -1 ) = 0 so x=0 or x=1/8..
9. (Original post by Zacken)
I think you mean x^{-\frac{1}{3}}, use the curly brackets.
oh ok it just looked a little weird when i edited it
10. (Original post by Bath~Student)
Not inherently incorrect.

But I feel your method is rather awkward.

Why not cube both sides, factor out an x^2 giving x^2 ( 8x -1 ) = 0 so x=0 or x=1/8..
It's entirely correct.

Because I don't want to.
11. (Original post by Bath~Student)
Not inherently incorrect.

But I feel your method is rather awkward.

Why not cube both sides, factor out an x^2 giving x^2 ( 8x -1 ) = 0 so x=0 or x=1/8..
Well then saying 'false' is completely unjustified.
But the quickest method is noting that is a solution, then dividing by to get the other one immediately.
12. (Original post by Zacken)
It's entirely correct.

Because I don't want to.
It is.

But it is beyond ugly factoring out an x and having the reciprocal of x to the third power in your brackets.
13. After that step x^2 = 6x
So x^2 - 6x=0
Now you have a quadratic
x(x -6)=0
x=0 or x =6
14. (Original post by IrrationalRoot)
Well then saying 'false' is completely unjustified.
But the quickest method is noting that is a solution, then dividing by to get the other one immediately.
I fully concur. Why one would want the reciprocal of x to the third power within the factoring brackets is beyond me. But then I am not a future snob-university mathematician, so what do I know?
15. (Original post by sabana)
After that step x^2 = 6x
So x^2 - 6x=0
Now you have a quadratic
x(x -6)=0
x=0 or x =6
errrrr
16. (Original post by sabana)
After that step x^2 = 6x
So x^2 - 6x=0
Now you have a quadratic
x(x -6)=0
x=0 or x =6
The OP means 3x^(2/3) = 6x.
17. (Original post by Zacken)
The OP means 3x^(2/3) = 6x.
Ooops my mistake sorry
18. (Original post by sabana)
Ooops my mistake sorry
No worries, I can see why you'd be confused though, don't worry about it!
19. (Original post by Zacken)
No worries, I can see why you'd be confused though, don't worry about it!
What a philanthropist.
20. (Original post by Zacken)
It's entirely correct.

Because I don't want to.
(Original post by Bath~Student)
It is.

But it is beyond ugly factoring out an x and having the reciprocal of x to the third power in your brackets.
Have to agree with Bath Student, there is much simpler way to solve this not involving the reciprocal and third power, just confusing OP otherwise.

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Updated: April 18, 2016
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