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# The relationship whereby when speed increases so does the kinetic energy, help! Watch

1. So, I understand that V^2 is the speed, so therefore if the speed increases, so must the kinetic energy.
However, I don't get how this revision guide states things like "if you go twice as fast, the braking distance must increase by a factor of four to convert the extra KE."
I understand that statement, but what does it mean by "a factor of four". Elsewhere in the image, it says "increasing the speed by a factor of 3 increases the KE by a factor of 3^2 (=9)". It also says "If you double the speed, you double the value of v, bnut the v^2 means that the KE is then increased by a factor of four".

What does the "factor of four" mean and the factor of three? Please can you explain it to me?

Thank you for your time

2. (Original post by blobbybill)
So, I understand that V^2 is the speed, so therefore if the speed increases, so must the kinetic energy.
However, I don't get how this revision guide states things like "if you go twice as fast, the braking distance must increase by a factor of four to convert the extra KE."
I understand that statement, but what does it mean by "a factor of four". Elsewhere in the image, it says "increasing the speed by a factor of 3 increases the KE by a factor of 3^2 (=9)". It also says "If you double the speed, you double the value of v, bnut the v^2 means that the KE is then increased by a factor of four".

What does the "factor of four" mean and the factor of three? Please can you explain it to me?

Thank you for your time

multiplied by 4 or multiplied by 3

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