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The relationship whereby when speed increases so does the kinetic energy, help! Watch

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    So, I understand that V^2 is the speed, so therefore if the speed increases, so must the kinetic energy.
    However, I don't get how this revision guide states things like "if you go twice as fast, the braking distance must increase by a factor of four to convert the extra KE."
    I understand that statement, but what does it mean by "a factor of four". Elsewhere in the image, it says "increasing the speed by a factor of 3 increases the KE by a factor of 3^2 (=9)". It also says "If you double the speed, you double the value of v, bnut the v^2 means that the KE is then increased by a factor of four".

    What does the "factor of four" mean and the factor of three? Please can you explain it to me?


    Thank you for your time

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    (Original post by blobbybill)
    So, I understand that V^2 is the speed, so therefore if the speed increases, so must the kinetic energy.
    However, I don't get how this revision guide states things like "if you go twice as fast, the braking distance must increase by a factor of four to convert the extra KE."
    I understand that statement, but what does it mean by "a factor of four". Elsewhere in the image, it says "increasing the speed by a factor of 3 increases the KE by a factor of 3^2 (=9)". It also says "If you double the speed, you double the value of v, bnut the v^2 means that the KE is then increased by a factor of four".

    What does the "factor of four" mean and the factor of three? Please can you explain it to me?


    Thank you for your time

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Views: 31
Size:  524.5 KB
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