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    • Thread Starter

    Been a good few years since I tackled some questions like these. Anyone able to help me?
    'A ball is thrown out of a window 18m above the ground. It is thrown horizontally at 5.0m/s.
    (a). Show that it takes about 2 seconds to reach the ground. (g = 9.8ms^-2)
    (b) calculate the distance from the bottom of the building to the place where the ball hits the ground.'

    For the first one you'll need to look at the values you have a look for a suvat equation that you can place values into to work out t (considering that u=0 when the ball is dropped from a height).

    For the second part you'll just multiply the component of the velocity that the ball travels along by the time it takes to do so.

    Hey there!
    Just attempted that question now and here's my working. Is everything clear enough? I hope I laid it out alright please say if it isn't, I'll gladly explain more if needed.
    I've scanned it in as it looks better than a picture of it here
    Just hope it's all correct!
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