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# Stats help watch

1. it looks like both a and c are the right answrs
2. (Original post by WarriorOfPeace)
it looks like both a and c are the right answrs
What conditions have to be satisfied for a function to be a pdf? A cdf?

3. for the pdf

If it's such that c =2 then cdf is and c=0.5 then the cdf is
4. (Original post by WarriorOfPeace)

for the pdf

If it's such that c =2 then cdf is and c=0.5 then the cdf is
What is the value of

?

What can you therefore deduce about the possible value of c?
5. (Original post by Gregorius)
What is the value of

?

What can you therefore deduce about the possible value of c?
not sure how to latex this? (cx^2 / 2 ) = 1 so c = 1/2 when the limits of 0 to 2 are used?
6. (Original post by WarriorOfPeace)
not sure how to latex this? (cx^2 / 2 ) = 1 so c = 1/2 when the limits of 0 to 2 are used?
So is possible? Is still a p.d.f if ?
7. (Original post by Zacken)
So is possible? Is still a p.d.f if ?
If I replace c with 2 from the start it works, no? C = 1/2 works
8. (Original post by WarriorOfPeace)
If I replace c with 2 from the start it works, no? C = 1/2 works
Are you sure that between and everywhere else is a P.D.F?

Check: Does ?
9. As an additional check, one can note that F(2)=4 for a,b, which is impossible for a cdf.

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