Correct me if I'm having a brain fart. If not, I wonder if they caught that and corrected it, or if teachers caught it themselves when marking, otherwise it's awful to think what effect on grades they'd have.
3biii) It asks, hence, for the overall percentage uncertainty in k, that is to combine the answers to 3bi and 3bii, which are the percentage uncertainties of T and d respectively (because k = Td).
However in the mark scheme it combines the answer for 3a (0.8) and 3b ii (0.1), but 3a was working out what k is, so they've combined the actual value of k with one of the percentage uncertainties... (That or they've got confused and used the value of d from the previous question for some reason...)
4b) The mark scheme references '3aii', a question that doesn't exist, the answer to which is supposedly 0.8%. 0.8 was the answer to 3a, which (as above) was just the value of k (or d in the working of 3bii), not even a percentage!
2d) The gradient. With all the points plotted correctly, and the correct calculation, I came to -0.82. The answer given is anywhere between -0.97 and -1.05. What did anyone else get? Because to get that I can't think of a line where the points are equally both sides.