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# Proving SUVAT Equation June 2009 watch

1. Attached is a graph of velocity against time.
My question is to prove that

s = ut + 1/2at^2

I start by finding the area of the rectangle, knowing that the area under the line gives displacement.

s = ut

I then find the area of the triangle

1/2 (v-u) * t

= 1/2 * at * t
= 1/2at^2

So I thought that the rectangle - area gives the area
being s = ut - 1/2 at^2

but why is this not the case?
Attached Images

2. Update - i am so silly sorry i noticed the mistake.
3. (Original post by nwmyname)
Attached is a graph of velocity against time.
My question is to prove that

s = ut + 1/2at^2

I start by finding the area of the rectangle, knowing that the area under the line gives displacement.

s = ut

I then find the area of the triangle

1/2 (v-u) * t

= 1/2 * at * t
= 1/2at^2

So I thought that the rectangle - area gives the area
being s = ut - 1/2 at^2

but why is this not the case?
you're trying to do this...

4. (Original post by Joinedup)
you're trying to do this...

I know haha I looked at it from completely the wrong way!

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