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    Hey.
    https://983c9f06eb1f75af6e83364e092b...20C4%20OCR.pdf
    Could somone explain question 9 (i) to be i was able to the a theta value for a by using the fact that DY/DX=0 as its a turning point but i dont see what to use for B.
    Thanks
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    (Original post by SamuelN98)
    Hey.
    https://983c9f06eb1f75af6e83364e092b...20C4%20OCR.pdf
    Could somone explain question 9 (i) to be i was able to the a theta value for a by using the fact that DY/DX=0 as its a turning point but i dont see what to use for B.
    Thanks
    At B, y = 0.

    For A you don't need dy/dx, just use the fact that y is maximum at A and consider \sin \theta.
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    (Original post by notnek)
    At B, y = 0.

    For A you don't need dy/dx, just use the fact that y is maximum at A and consider \sin \theta.
    For B how do i determine which value of theta that makes sine(theta)=0 to use.
    0, \pi or 2 \pi ?
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    (Original post by SamuelN98)
    For B how do i determine which value of theta that makes sine(theta)=0 to use.
    0,pie or 2 pie?
    Well, you know it can't be 0 since that would make x be 0 as well. Now can you justify what it is between pi and 2pi using the position of A?
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    (Original post by SamuelN98)
    For B how do i determine which value of theta that makes sine(theta)=0 to use.
    0,pie or 2 pie?
    Plug these values of \theta into x then determine which one of these coordinates must be B.
 
 
 
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