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    For part A, can't lithium be an answer as well because it gets oxidised from +1 to +2?


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    Li 1s2 2s1
    Li+ i.e. oxid. state +1 1s2
    Li2+ i.e. oxide state +2 1s1 NO WAY HOSE

    Co is your man.
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    (Original post by Pigster)
    Li 1s2 2s1
    Li+ i.e. oxid. state +1 1s2
    Li2+ i.e. oxide state +2 1s1 NO WAY HOSE

    Co is your man.
    Yeah but lithium is getting oxidised as well!!


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    (Original post by Lilly1234567890)
    Yeah but lithium is getting oxidised as well!!


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    There's no way you could take another electron from Li+.
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    Hi Lily1234567890

    The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.

    Li+ + CoO2 + e- --> Li+(CoO2)-

    Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.

    I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.

    Alex
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    (Original post by ajsullivan)
    Hi Lily1234567890

    The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.

    Li+ + CoO2 + e- --> Li+(CoO2)-

    Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.

    I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.

    Alex
    O yea got it now after reading question again! Thanks !


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